Return exit code

StewartBW 745 Reputation points
2024-06-17T22:47:17.3233333+00:00

Hello,

I have 2 VB.net WinForms app (.net 4.0) one is x64 one is x86

From the x64 one, I call the x86 one and need to get back its return code.

Code inside the x64 app:

        Using Compiler As New Process
            Compiler.StartInfo.WorkingDirectory = My.Application.Info.DirectoryPath
            Compiler.StartInfo.FileName = "App.exe"
            Compiler.StartInfo.UseShellExecute = False
            Compiler.StartInfo.RedirectStandardOutput = False
            Compiler.StartInfo.WindowStyle = ProcessWindowStyle.Hidden
            Compiler.EnableRaisingEvents = True
            Compiler.Start()
            Compiler.WaitForExit()
            If Compiler.HasExited = False Then
                Compiler.Kill()
            Else
                MsgBox(Compiler.ExitCode)
            End If
        End Using

And the second x86 app, in the form load., I use:

Environment.ExitCode = xxx
'Environment.Exit(xxx)
Application.Exit()

The problem is that I always get zero as return code :(

Anyone knows why?

Thanks.

VB
VB
An object-oriented programming language developed by Microsoft that is implemented on the .NET Framework. Previously known as Visual Basic .NET.
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  1. StewartBW 745 Reputation points
    2024-06-18T04:15:55.66+00:00

    Thanks all, when called from the other app.exe, it always returned zero until I disabled Application Framework and set the ExitCode in the New / Finalize

    No idea if it can work with Application Framework enabled or not :(


  2. Jiachen Li-MSFT 28,001 Reputation points Microsoft Vendor
    2024-06-18T07:28:08.82+00:00

    Hi @StewartBW

    Disabling the Application Framework ensures that your custom exit code logic is not overridden.

    Best Regards.

    Jiachen Li


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