SrgsRule Constructors

Source:

SrgsRule.cs

Source:

SrgsRule.cs

public:
 SrgsRule(System::String ^ id);

public SrgsRule (string id);

new System.Speech.Recognition.SrgsGrammar.SrgsRule : string -> System.Speech.Recognition.SrgsGrammar.SrgsRule

Public Sub New (id As String)

Parameters

Exceptions

Examples

The following example creates a grammar that recognizes the phrase "A nation that has won the World Cup is" followed by the name of a country that has won the World Cup. The example creates a SrgsRule object named winnerRule and passes in the identifier WorldCupWinner as a String. The SrgsOneOf object consists of an array of new SrgsItem objects containing alternatives to be recognized by the rule.

public void WorldSoccerWinners ()
{

  // Create an SrgsDocument, create a new rule
  // and set its scope to public.
  SrgsDocument document = new SrgsDocument();
  SrgsRule winnerRule = new SrgsRule("WorldCupWinner");
  winnerRule.Scope = SrgsRuleScope.Public;

  // Add the introduction.
  winnerRule.Elements.Add(new SrgsItem("A nation that has won the world cup is: "));

  // Create the rule for the European nations.
  SrgsOneOf oneOfEurope = new SrgsOneOf(new SrgsItem[] {new SrgsItem("England"),
    new SrgsItem("France"), new SrgsItem("Germany"), new SrgsItem("Italy")});
  SrgsRule ruleEurope = (new SrgsRule("EuropeanNations", new SrgsElement[] {oneOfEurope}));

  // Create the rule for the South American nations.
  SrgsOneOf oneOfSAmerica = new SrgsOneOf(new SrgsItem[] {new SrgsItem("Argentina"),
    new SrgsItem("Brazil"), new SrgsItem("Uruguay")});
  SrgsRule ruleSAmerica = (new SrgsRule("SouthAmericanNations", new SrgsElement[] {oneOfSAmerica}));

  // Add references to winnerRule for ruleEurope and ruleSAmerica.
  winnerRule.Elements.Add(new SrgsOneOf(new SrgsItem[] {(new SrgsItem
    (new SrgsRuleRef(ruleEurope))), new SrgsItem(new SrgsRuleRef(ruleSAmerica))}));

  // Add all the rules to the document and make winnerRule
  // the root rule of the document.
  document.Rules.Add(new SrgsRule[] {winnerRule, ruleEurope, ruleSAmerica});
  document.Root = winnerRule;
}

Remarks

The SrgsRule constructor initializes the Id property. The identifier must be unique within a given grammar.

The SrgsRule constructor throws a FormatException in the following circumstances:

• id is not a valid XML name, as defined in Extensible Markup Language (XML) 1.0 (Fifth Edition). To paraphrase this definition, a valid XML name must begin with a letter, an underscore ('_'), or a colon (':') and can be followed by zero or more NameChar characters (also defined in the XML specification).

• id is "NULL" or "VOID" or "GARBAGE".

• id contains at least one invalid rule ID character. These characters are: '?', '*', '+', '|', '(', '), '^', '$', '/', ';', '.', '=', '<', '>', '[', ']', '{', '}', '\\', ' ', '\t', '\r', and '\n'.

See also

• Create Grammars Using SrgsGrammar

Source:

SrgsRule.cs

Source:

SrgsRule.cs

public:
 SrgsRule(System::String ^ id, ... cli::array <System::Speech::Recognition::SrgsGrammar::SrgsElement ^> ^ elements);

public SrgsRule (string id, params System.Speech.Recognition.SrgsGrammar.SrgsElement[] elements);

new System.Speech.Recognition.SrgsGrammar.SrgsRule : string * System.Speech.Recognition.SrgsGrammar.SrgsElement[] -> System.Speech.Recognition.SrgsGrammar.SrgsRule

Public Sub New (id As String, ParamArray elements As SrgsElement())

Parameters

Exceptions

Examples

The following example creates a grammar that recognizes the phrase "A nation that has won the World Cup is" followed by the name of a country that has won the World Cup. The example creates a public rule named WorldCupWinner. The example then creates two SrgsRule objects, ruleEurope and ruleSAmerica, passing in a String for the rule identifier and an SrgsElement array containing a SrgsOneOf object. Subsequently, the example adds rule references to ruleEurope and ruleSAmerica from the rule WorldCupWinner.

public void WorldSoccerWinners ()
{
  // Create a grammar from an SRGSDocument, create a new rule
  // and set its scope to public.
  SrgsDocument srgsGrammar = new SrgsDocument ();
  SrgsRule winnerRule = new SrgsRule ("WorldCupWinner");
  winnerRule.Scope = SrgsRuleScope.Public;

  // Add the introduction.
  winnerRule.Elements.Add (new SrgsItem ("A nation that has won the world cup is"));

  // Create the rule for the European nations.
  SrgsOneOf oneOfEurope = new SrgsOneOf(new SrgsItem[] {new SrgsItem("England"), new SrgsItem("France"), new SrgsItem("Germany"), new SrgsItem("Italy")});
  SrgsRule ruleEurope = (new SrgsRule("EuropeanNations", new SrgsElement[] {oneOfEurope}));

  // Create the rule for the South American nations.
  SrgsOneOf oneOfSAmerica = new SrgsOneOf(new SrgsItem[] {new SrgsItem("Argentina"), new SrgsItem("Brazil"), new SrgsItem("Uruguay")});
  SrgsRule ruleSAmerica = (new SrgsRule("SouthAmericanNations", new SrgsElement[] {oneOfSAmerica}));

  // Add references to winnerRule for ruleEurope and ruleSAmerica.
  winnerRule.Elements.Add(new SrgsOneOf(new SrgsItem[] {(new SrgsItem (new SrgsRuleRef(ruleEurope))), new SrgsItem(new SrgsRuleRef(ruleSAmerica))}));

  // Add all the rules to the grammar and make winnerRule
  // the root rule of the grammar.
  document.Rules.Add(new SrgsRule[] {winnerRule, ruleEurope, ruleSAmerica});
  srgsGrammar.Root = winnerRule;
}

The created grammar has the following form.

<grammar version="1.0" xml:lang="en-US" xmlns="http://www.w3.org/2001/06/grammar" root="WorldCupWinner">
    <rule id="WorldCupWinner" scope="public">
        <item> A nation that has won the world cup is </item>
        <one-of>
            <item>
                <ruleref uri="#EuropeanNations" />
            </item>
            <item>
                <ruleref uri="#SouthAmericanNations" />
            </item>
        </one-of>
    </rule>
    <rule id="EuropeanNations">
        <one-of>
            <item> England </item>
            <item> France </item>
            <item> Germany </item>
            <item> Italy </item>
        </one-of>
    </rule>
    <rule id="SouthAmericanNations">
        <one-of>
            <item> Argentina </item>
            <item> Brazil </item>
            <item> Uruguay </item>
        </one-of>
    </rule>
</grammar>

Remarks

The SrgsRule constructor initializes the Id property. The identifier must be unique within a given grammar.

The SrgsRule constructor throws a FormatException in the following circumstances:

• id is not a valid XML name, as defined in Extensible Markup Language (XML) 1.0 (Fifth Edition). To paraphrase this definition, a valid XML name must begin with a letter, an underscore ('_'), or a colon (':') and can be followed by zero or more NameChar characters (also defined in the XML specification).

• id is "NULL" or "VOID" or "GARBAGE".

• id contains at least one invalid rule ID character. These characters are: '?', '*', '+', '|', '(', '), '^', '$', '/', ';', '.', '=', '<', '>', '[', ']', '{', '}', '\\', ' ', '\t', '\r', and '\n'.

See also

• Create Grammars Using SrgsGrammar