Propriété Logins

Représente une collection d'objets Login. Chaque objet Login représente une connexion définie sur l'instance de SQL Server.

Espace de noms :  Microsoft.SqlServer.Management.Smo
Assembly :  Microsoft.SqlServer.Smo (en Microsoft.SqlServer.Smo.dll)

Syntaxe

'Déclaration
<SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny,  _
    GetType(Login))> _
Public ReadOnly Property Logins As LoginCollection
    Get
'Utilisation
Dim instance As Server
Dim value As LoginCollection

value = instance.Logins
[SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny, 
    typeof(Login))]
public LoginCollection Logins { get; }
[SfcObjectAttribute(SfcContainerRelationship::ObjectContainer, SfcContainerCardinality::ZeroToAny, 
    typeof(Login))]
public:
property LoginCollection^ Logins {
    LoginCollection^ get ();
}
[<SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny, 
    typeof(Login))>]
member Logins : LoginCollection
function get Logins () : LoginCollection

Valeur de propriété

Type : Microsoft.SqlServer.Management.Smo. . :: . .LoginCollection
Objet LoginCollection qui représente toutes les connexions définies sur l'instance de SQL Server.

Notes

The Logins property points to the LoginCollection object. The collection can be used to enumerate all the logins for the instance of SQL Server. If you are using Windows Authentication only, the Logins property represents Windows-authenticated accounts. With Mixed Mode Authentication, this property also represents accounts that are created by using SQL Server Authentication.

Exemples

Visual Basic

'Connect to the local, default instance of SQL Server.
Dim srv As Server
srv = New Server
'Display the logins on the instance of SQL Server.
Dim lg As Login
For Each lg In srv.Logins
   Console.WriteLine(lg.Name)
Next

PowerShell

$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
foreach ($lg in $srv.Logins)
{
   Write-Host $lg.Name
}