XObject.NodeType Property

Property Value

Type: System.Xml.XmlNodeType
The node type for this XObject.

Dim output As New StringBuilder
' Note that XNode uses XmlNodeType, which is in the System.Xml  namespace.
Dim xmlTree As XDocument = _
    <?xml version="1.0"?>
    <!--a comment-->
    <?xml-stylesheet type="text/xsl" href="hello.xsl"?>
    <Root Att="attContent">
        <Child1><![CDATA[CDATA content]]></Child1>
        <Child2>Text content</Child2>
    </Root>

For Each node As XNode In xmlTree.DescendantNodes
    output.Append(node.NodeType.ToString())
    output.Append(Environment.NewLine)
    If node.NodeType = XmlNodeType.Element Then
        For Each att In DirectCast(node, XElement).Attributes
            output.Append(att.NodeType.ToString())
            output.Append(Environment.NewLine)
        Next
    End If
Next


OutputTextBlock.Text = output.ToString()

StringBuilder output = new StringBuilder();
// Note that XNode uses XmlNodeType, which is in the System.Xml namespace.
XDocument xmlTree = new XDocument(
    new XComment("a comment"),
    new XProcessingInstruction("xml-stylesheet", "type=\"text/xsl\" href=\"hello.xsl\""),
    new XElement("Root",
        new XAttribute("Att", "attContent"),
        new XElement("Child1",
            new XCData("CDATA content")
        ),
        new XElement("Child2",
            new XText("Text content")
        )
    )
);

foreach (XNode node in xmlTree.DescendantNodes())
{
    output.Append(node.NodeType + Environment.NewLine);
    if (node.NodeType == XmlNodeType.Element)
    {
        foreach (XAttribute att in ((XElement)node).Attributes())
            output.Append(att.NodeType + Environment.NewLine);
    }
}

OutputTextBlock.Text = output.ToString();