CodeGenerationUtilities.GetBaseDomainClassSchemaTypeName Method
Definition
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Get the schema type name for the base class of the given domain class.
public:
static System::String ^ GetBaseDomainClassSchemaTypeName(Microsoft::VisualStudio::Modeling::DslDefinition::DomainClass ^ domainClass, System::String ^ currentNamespace, System::Collections::Generic::Dictionary<Microsoft::VisualStudio::Modeling::DslDefinition::DslLibrary ^, System::String ^> ^ xmlNamespaceQualifiers);public static string GetBaseDomainClassSchemaTypeName (Microsoft.VisualStudio.Modeling.DslDefinition.DomainClass domainClass, string currentNamespace, System.Collections.Generic.Dictionary<Microsoft.VisualStudio.Modeling.DslDefinition.DslLibrary,string> xmlNamespaceQualifiers);static member GetBaseDomainClassSchemaTypeName : Microsoft.VisualStudio.Modeling.DslDefinition.DomainClass * string * System.Collections.Generic.Dictionary<Microsoft.VisualStudio.Modeling.DslDefinition.DslLibrary, string> -> stringPublic Shared Function GetBaseDomainClassSchemaTypeName (domainClass As DomainClass, currentNamespace As String, xmlNamespaceQualifiers As Dictionary(Of DslLibrary, String)) As StringParameters
- domainClass
- DomainClass
DomainClass whose base class schema type name will be returned.
- currentNamespace
- String
- xmlNamespaceQualifiers
- Dictionary<DslLibrary,String>
Returns
The schema type name of the base class of the given DomainClass or null if a base class could not be determined.