InOutArgument<T>.Expression プロパティ

  • リファレンス

定義

名前空間:
System.Activities
アセンブリ:
System.Activities.dll

この Activity<TResult> の値を表す InOutArgument<T> を取得します。

public:
 property System::Activities::Activity<System::Activities::Location<T> ^> ^ Expression { System::Activities::Activity<System::Activities::Location<T> ^> ^ get(); void set(System::Activities::Activity<System::Activities::Location<T> ^> ^ value); };
public System.Activities.Activity<System.Activities.Location<T>> Expression { get; set; }
member this.Expression : System.Activities.Activity<System.Activities.Location<'T>> with get, set
Public Property Expression As Activity(Of Location(Of T))

プロパティ値

Activity<Location<T>>

引数の値です。

適用対象