XmlIncludeAttribute.Type プロパティ
定義
重要
一部の情報は、リリース前に大きく変更される可能性があるプレリリースされた製品に関するものです。 Microsoft は、ここに記載されている情報について、明示または黙示を問わず、一切保証しません。
含めるオブジェクトの型を取得または設定します。
public:
property Type ^ Type { Type ^ get(); void set(Type ^ value); };
public Type Type { get; set; }
public Type? Type { get; set; }
member this.Type : Type with get, set
Public Property Type As Type
プロパティ値
含めるオブジェクトの Type。
例
次の例では、 という名前 Group
のクラスを定義します。このクラスには、 オブジェクトの配列を返す という名前 Employees
の Employee
フィールドが含まれています。 この例では、 Manager
クラスから クラスをEmployee
派生させ、 を クラスにEmployee
適用しますXmlIncludeAttribute。 この例では、 オブジェクトを Group
作成するときに、 オブジェクトを Manager
配列に Employee
挿入します。 最後に、この例では オブジェクトを Group
シリアル化します。
#using <System.Xml.dll>
#using <System.dll>
using namespace System;
using namespace System::IO;
using namespace System::Xml::Serialization;
ref class Employee;
ref class Manager;
ref class Group
{
public:
array<Employee^>^Employees;
};
// Instruct the XmlSerializer to accept Manager types as well.
[XmlInclude(Manager::typeid)]
public ref class Employee
{
public:
String^ Name;
};
public ref class Manager: public Employee
{
public:
int Level;
};
void SerializeObject( String^ filename )
{
XmlSerializer^ s = gcnew XmlSerializer( Group::typeid );
TextWriter^ writer = gcnew StreamWriter( filename );
Group^ group = gcnew Group;
Manager^ manager = gcnew Manager;
Employee^ emp1 = gcnew Employee;
Employee^ emp2 = gcnew Employee;
manager->Name = "Zeus";
manager->Level = 2;
emp1->Name = "Ares";
emp2->Name = "Artemis";
array<Employee^>^emps = {manager,emp1,emp2};
group->Employees = emps;
s->Serialize( writer, group );
writer->Close();
}
void DeserializeObject( String^ filename )
{
FileStream^ fs = gcnew FileStream( filename,FileMode::Open );
XmlSerializer^ x = gcnew XmlSerializer( Group::typeid );
Group^ g = dynamic_cast<Group^>(x->Deserialize( fs ));
Console::Write( "Members:" );
System::Collections::IEnumerator^ myEnum = g->Employees->GetEnumerator();
while ( myEnum->MoveNext() )
{
Employee^ e = safe_cast<Employee^>(myEnum->Current);
Console::WriteLine( "\t{0}", e->Name );
}
}
int main()
{
SerializeObject( "IncludeExample.xml" );
DeserializeObject( "IncludeExample.xml" );
}
using System;
using System.IO;
using System.Xml.Serialization;
public class Group
{
public Employee[] Employees;
}
// Instruct the XmlSerializer to accept Manager types as well.
[XmlInclude(typeof(Manager))]
public class Employee
{
public string Name;
}
public class Manager:Employee
{
public int Level;
}
public class Run
{
public static void Main()
{
Run test = new Run();
test.SerializeObject("IncludeExample.xml");
test.DeserializeObject("IncludeExample.xml");
}
public void SerializeObject(string filename)
{
XmlSerializer s = new XmlSerializer(typeof(Group));
TextWriter writer = new StreamWriter(filename);
Group group = new Group();
Manager manager = new Manager();
Employee emp1 = new Employee();
Employee emp2 = new Employee();
manager.Name = "Zeus";
manager.Level = 2;
emp1.Name = "Ares";
emp2.Name = "Artemis";
Employee [] emps = new Employee[3]{manager, emp1, emp2};
group.Employees = emps;
s.Serialize(writer, group);
writer.Close();
}
public void DeserializeObject(string filename)
{
FileStream fs = new FileStream(filename, FileMode.Open);
XmlSerializer x = new XmlSerializer(typeof(Group));
Group g = (Group) x.Deserialize(fs);
Console.Write("Members:");
foreach(Employee e in g.Employees)
{
Console.WriteLine("\t" + e.Name);
}
}
}
Imports System.IO
Imports System.Xml.Serialization
Public Class Group
Public Employees() As Employee
End Class
' Instruct the XmlSerializer to accept Manager types as well.
<XmlInclude(GetType(Manager))> _
Public Class Employee
Public Name As String
End Class
Public Class Manager
Inherits Employee
Public Level As Integer
End Class
Public Class Run
Public Shared Sub Main()
Dim test As New Run()
test.SerializeObject("IncludeExample.xml")
test.DeserializeObject("IncludeExample.xml")
End Sub
Public Sub SerializeObject(ByVal filename As String)
Dim s As New XmlSerializer(GetType(Group))
Dim writer As New StreamWriter(filename)
Dim group As New Group()
Dim manager As New Manager()
Dim emp1 As New Employee()
Dim emp2 As New Employee()
manager.Name = "Zeus"
manager.Level = 2
emp1.Name = "Ares"
emp2.Name = "Artemis"
Dim emps() As Employee = {manager, emp1, emp2}
group.Employees = emps
s.Serialize(writer, group)
writer.Close()
End Sub
Public Sub DeserializeObject(ByVal filename As String)
Dim fs As New FileStream(filename, FileMode.Open)
Dim x As New XmlSerializer(GetType(Group))
Dim g As Group = CType(x.Deserialize(fs), Group)
Console.Write("Members:")
Dim e As Employee
For Each e In g.Employees
Console.WriteLine(ControlChars.Tab + e.Name)
Next e
End Sub
End Class
適用対象
GitHub で Microsoft と共同作業する
このコンテンツのソースは GitHub にあります。そこで、issue や pull request を作成および確認することもできます。 詳細については、共同作成者ガイドを参照してください。
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