複数のキーで要素を並べ替える方法 (LINQ to XML)
この記事では、C# および Visual Basic で複数のキーに基づいて並べ替える方法について示します。
例: 複数のキーで XML 要素を並べ替える
この例では、郵便番号 (プライマリ) と注文日の 2 つのキーで並べ替えます。 ここでは、XML ドキュメントの「サンプル XML ファイル: 顧客と注文」が使用されています。
XElement co = XElement.Load("CustomersOrders.xml");
var sortedElements =
from c in co.Element("Orders").Elements("Order")
orderby (string)c.Element("ShipInfo").Element("ShipPostalCode"),
(DateTime)c.Element("OrderDate")
select new {
CustomerID = (string)c.Element("CustomerID"),
EmployeeID = (string)c.Element("EmployeeID"),
ShipPostalCode = (string)c.Element("ShipInfo").Element("ShipPostalCode"),
OrderDate = (DateTime)c.Element("OrderDate")
};
foreach (var r in sortedElements)
Console.WriteLine("CustomerID:{0} EmployeeID:{1} ShipPostalCode:{2} OrderDate:{3:d}",
r.CustomerID, r.EmployeeID, r.ShipPostalCode, r.OrderDate);
Dim co As XElement = XElement.Load("CustomersOrders.xml")
Dim result = _
From c In co.<Orders>.<Order> _
Order By c.<ShipInfo>.<ShipPostalCode>.Value, Convert.ToDateTime(c.<OrderDate>.Value) _
Select New With { _
.CustomerID = c.<CustomerID>.Value, _
.EmployeeID = c.<EmployeeID>.Value, _
.ShipPostalCode = c.<ShipInfo>.<ShipPostalCode>.Value, _
.OrderDate = Convert.ToDateTime(c.<OrderDate>.Value) _
}
For Each r In result
Console.WriteLine("CustomerID:{0} EmployeeID:{1} ShipPostalCode:{2} OrderDate:{3:d}", _
r.CustomerID, r.EmployeeID, r.ShipPostalCode, r.OrderDate)
Next
この例を実行すると、次の出力が生成されます。
CustomerID:LETSS EmployeeID:1 ShipPostalCode:94117 OrderDate:6/25/1997
CustomerID:LETSS EmployeeID:8 ShipPostalCode:94117 OrderDate:10/27/1997
CustomerID:LETSS EmployeeID:6 ShipPostalCode:94117 OrderDate:11/10/1997
CustomerID:LETSS EmployeeID:4 ShipPostalCode:94117 OrderDate:2/12/1998
CustomerID:GREAL EmployeeID:6 ShipPostalCode:97403 OrderDate:5/6/1997
CustomerID:GREAL EmployeeID:8 ShipPostalCode:97403 OrderDate:7/4/1997
CustomerID:GREAL EmployeeID:1 ShipPostalCode:97403 OrderDate:7/31/1997
CustomerID:GREAL EmployeeID:4 ShipPostalCode:97403 OrderDate:7/31/1997
CustomerID:GREAL EmployeeID:6 ShipPostalCode:97403 OrderDate:9/4/1997
CustomerID:GREAL EmployeeID:3 ShipPostalCode:97403 OrderDate:9/25/1997
CustomerID:GREAL EmployeeID:4 ShipPostalCode:97403 OrderDate:1/6/1998
CustomerID:GREAL EmployeeID:3 ShipPostalCode:97403 OrderDate:3/9/1998
CustomerID:GREAL EmployeeID:3 ShipPostalCode:97403 OrderDate:4/7/1998
CustomerID:GREAL EmployeeID:4 ShipPostalCode:97403 OrderDate:4/22/1998
CustomerID:GREAL EmployeeID:4 ShipPostalCode:97403 OrderDate:4/30/1998
CustomerID:HUNGC EmployeeID:3 ShipPostalCode:97827 OrderDate:12/6/1996
CustomerID:HUNGC EmployeeID:1 ShipPostalCode:97827 OrderDate:12/25/1996
CustomerID:HUNGC EmployeeID:3 ShipPostalCode:97827 OrderDate:1/15/1997
CustomerID:HUNGC EmployeeID:4 ShipPostalCode:97827 OrderDate:7/16/1997
CustomerID:HUNGC EmployeeID:8 ShipPostalCode:97827 OrderDate:9/8/1997
CustomerID:LAZYK EmployeeID:1 ShipPostalCode:99362 OrderDate:3/21/1997
CustomerID:LAZYK EmployeeID:8 ShipPostalCode:99362 OrderDate:5/22/1997
例: 名前空間にある XML を並べ替える
この例では、最初と同じ並べ替えを行いますが、名前空間にある XML が対象になっています。 ここでは、XML ドキュメントのサンプル XML ファイル: 名前空間内の顧客と注文を使用しています。
詳細については、「名前空間の概要」を参照してください。
XElement co = XElement.Load("CustomersOrdersInNamespace.xml");
XNamespace aw = "http://www.adventure-works.com";
var sortedElements =
from c in co.Element(aw + "Orders").Elements(aw + "Order")
orderby (string)c.Element(aw + "ShipInfo").Element(aw + "ShipPostalCode"),
(DateTime)c.Element(aw + "OrderDate")
select new
{
CustomerID = (string)c.Element(aw + "CustomerID"),
EmployeeID = (string)c.Element(aw + "EmployeeID"),
ShipPostalCode = (string)c.Element(aw + "ShipInfo").Element(aw + "ShipPostalCode"),
OrderDate = (DateTime)c.Element(aw + "OrderDate")
};
foreach (var r in sortedElements)
Console.WriteLine("CustomerID:{0} EmployeeID:{1} ShipPostalCode:{2} OrderDate:{3:d}",
r.CustomerID, r.EmployeeID, r.ShipPostalCode, r.OrderDate);
Imports <xmlns='http://www.adventure-works.com'>
Module Module1
Sub Main()
Dim co As XElement = XElement.Load("CustomersOrdersInNamespace.xml")
Dim result = _
From c In co.<Orders>.<Order> _
Order By c.<ShipInfo>.<ShipPostalCode>.Value, Convert.ToDateTime(c.<OrderDate>.Value) _
Select New With { _
.CustomerID = c.<CustomerID>.Value, _
.EmployeeID = c.<EmployeeID>.Value, _
.ShipPostalCode = c.<ShipInfo>.<ShipPostalCode>.Value, _
.OrderDate = Convert.ToDateTime(c.<OrderDate>.Value) _
}
For Each r In result
Console.WriteLine("CustomerID:{0} EmployeeID:{1} ShipPostalCode:{2} OrderDate:{3:d}", _
r.CustomerID, r.EmployeeID, r.ShipPostalCode, r.OrderDate)
Next
End Sub
End Module
この例を実行すると、次の出力が生成されます。
CustomerID:LETSS EmployeeID:1 ShipPostalCode:94117 OrderDate:6/25/1997
CustomerID:LETSS EmployeeID:8 ShipPostalCode:94117 OrderDate:10/27/1997
CustomerID:LETSS EmployeeID:6 ShipPostalCode:94117 OrderDate:11/10/1997
CustomerID:LETSS EmployeeID:4 ShipPostalCode:94117 OrderDate:2/12/1998
CustomerID:GREAL EmployeeID:6 ShipPostalCode:97403 OrderDate:5/6/1997
CustomerID:GREAL EmployeeID:8 ShipPostalCode:97403 OrderDate:7/4/1997
CustomerID:GREAL EmployeeID:1 ShipPostalCode:97403 OrderDate:7/31/1997
CustomerID:GREAL EmployeeID:4 ShipPostalCode:97403 OrderDate:7/31/1997
CustomerID:GREAL EmployeeID:6 ShipPostalCode:97403 OrderDate:9/4/1997
CustomerID:GREAL EmployeeID:3 ShipPostalCode:97403 OrderDate:9/25/1997
CustomerID:GREAL EmployeeID:4 ShipPostalCode:97403 OrderDate:1/6/1998
CustomerID:GREAL EmployeeID:3 ShipPostalCode:97403 OrderDate:3/9/1998
CustomerID:GREAL EmployeeID:3 ShipPostalCode:97403 OrderDate:4/7/1998
CustomerID:GREAL EmployeeID:4 ShipPostalCode:97403 OrderDate:4/22/1998
CustomerID:GREAL EmployeeID:4 ShipPostalCode:97403 OrderDate:4/30/1998
CustomerID:HUNGC EmployeeID:3 ShipPostalCode:97827 OrderDate:12/6/1996
CustomerID:HUNGC EmployeeID:1 ShipPostalCode:97827 OrderDate:12/25/1996
CustomerID:HUNGC EmployeeID:3 ShipPostalCode:97827 OrderDate:1/15/1997
CustomerID:HUNGC EmployeeID:4 ShipPostalCode:97827 OrderDate:7/16/1997
CustomerID:HUNGC EmployeeID:8 ShipPostalCode:97827 OrderDate:9/8/1997
CustomerID:LAZYK EmployeeID:1 ShipPostalCode:99362 OrderDate:3/21/1997
CustomerID:LAZYK EmployeeID:8 ShipPostalCode:99362 OrderDate:5/22/1997
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