basic_string::find_last_of

特定の文字列の要素に一致する最後の文字の文字列を調べ。

size_type find_last_of(
    value_type _Ch, 
    size_type _Off = npos
) const;

size_type find_last_of(
    const value_type* _Ptr,
    size_type _Off = npos
) const;

size_type find_last_of(
    const value_type* _Ptr, 
    size_type _Off,
    size_type _Count
) const;

size_type find_last_of(
    const basic_string<CharType, Traits, Allocator>& _Str,
    size_type _Off = npos
) const;

パラメーター

  • _Ch
    検索するメンバー関数がであるリテラル値。

  • _Off
    検索が完了するまでになる位置のインデックス。

  • _Ptr
    検索するメンバー関数が C 文字列。

  • _Count
    最初の文字からの方向にカウント文字数 C 文字列がメンバー関数が検索することです。

  • _Str
    メンバー関数がであるは The string 検索する。

戻り値

部分文字列の最後の文字のインデックスが成功した場合はを捜しました; それ npos

使用例

// basic_string_find_last_of.cpp
// compile with: /EHsc
#include <string>
#include <iostream>

int main( )
{
   using namespace std;

   // The first member function
   // searches for a single character in a string
   string str1 ( "abcd-1234-abcd-1234" );
   cout << "The original string str1 is: " << str1 << endl;
   basic_string <char>::size_type indexCh1a, indexCh1b;
   static const basic_string <char>::size_type npos = -1;

   indexCh1a = str1.find_last_of ( "d" , 14 );
   if ( indexCh1a != npos )
      cout << "The index of the last 'd' found before the 14th"
           << " position in str1 is: " << indexCh1a << endl;
   else
      cout << "The character 'd' was not found in str1 ." << endl;

   indexCh1b = str1.find_first_of ( "x" );
   if ( indexCh1b != npos )
      cout << "The index of the 'x' found in str1 is: "
           << indexCh1b << endl << endl;
   else
      cout << "The character 'x' was not found in str1."
           << endl << endl;

   // The second member function searches a string
   // for a substring as specified by a C-string
   string str2 ( "ABCD-1234-ABCD-1234" );
   cout << "The original string str2 is: " << str2 << endl;
   basic_string <char>::size_type indexCh2a, indexCh2b;

   const char *cstr2 = "B1";
   indexCh2a = str2.find_last_of  ( cstr2 , 12 );
   if (indexCh2a != npos )
      cout << "The index of the last occurrence of an "
           << "element of 'B1' in str2 before\n the 12th "
           << "position is: " << indexCh2a << endl;
   else
      cout << "Elements of the substring 'B1' were not "
           << "found in str2 before the 12th position."
           << endl;

   const char *cstr2b = "D2";
   indexCh2b = str2.find_last_of  ( cstr2b );
   if ( indexCh2b != npos )
      cout << "The index of the last element of 'D2' "
           << "after\n the 0th position in str2 is: "
           << indexCh2b << endl << endl;
   else
      cout << "The substring 'D2' was not found in str2 ."
           << endl << endl << endl;

   // The third member function searches a string
   // for a substring as specified by a C-string
   string str3 ( "456-EFG-456-EFG" );
   cout << "The original string str3 is: " << str3 << endl;
   basic_string <char>::size_type indexCh3a;

   const char *cstr3a = "5E";
   indexCh3a = str3.find_last_of ( cstr3a , 8 , 8 );
   if ( indexCh3a != npos )
      cout << "The index of the last occurrence of an "
           << "element of '5E' in str3 before\n the 8th "
           << "position is: " << indexCh3a << endl << endl;
   else
      cout << "Elements of the substring '5G' were not "
           << "found in str3\n before the 8th position."
           << endl << endl;

   // The fourth member function searches a string
   // for a substring as specified by a string
   string str4 ( "12-ab-12-ab" );
   cout << "The original string str4 is: " << str4 << endl;
   basic_string <char>::size_type indexCh4a, indexCh4b;

   string str4a ( "ba3" );
   indexCh4a = str4.find_last_of  ( str4a , 8 );
   if ( indexCh4a != npos )
      cout << "The index of the last occurrence of an "
           << "element of 'ba3' in str4 before\n the 8th "
           << "position is: " << indexCh4a << endl;
   else
      cout << "Elements of the substring 'ba3' were not "
           << "found in str4\n after the 0th position."
           << endl;

   string str4b ( "a2" );
   indexCh4b = str4.find_last_of ( str4b  );
   if ( indexCh4b != npos )
      cout << "The index of the last occurrence of an "
           << "element of 'a2' in str4 before\n the 0th "
           << "position is: " << indexCh4b << endl;
   else
      cout << "Elements of the substring 'a2' were not "
           << "found in str4\n after the 0th position."
           << endl;
}
  
  

必要条件

ヘッダー: <string>

名前空間: std

参照

関連項目

basic_string Class