DateTimeFormatInfo.LongDatePattern Propriedade

  • Referência

Definição

Namespace:
System.Globalization
Assembly:
System.Globalization.dll
Assembly:
System.Runtime.dll
Assembly:
mscorlib.dll
Assembly:
netstandard.dll
Origem:
DateTimeFormatInfo.cs
Origem:
DateTimeFormatInfo.cs
Origem:
DateTimeFormatInfo.cs

Obtém ou define a cadeia de caracteres de formato personalizado para um valor de data longa.

public:
 property System::String ^ LongDatePattern { System::String ^ get(); void set(System::String ^ value); };
public string LongDatePattern { get; set; }
member this.LongDatePattern : string with get, set
Public Property LongDatePattern As String

Valor da propriedade

String

A cadeia de caracteres de formato personalizado para um valor de data longa.

Exceções

ArgumentNullException

A propriedade está sendo definida como null.

InvalidOperationException

A propriedade está sendo definida e o objeto DateTimeFormatInfo é somente leitura.

Exemplos

O exemplo a seguir exibe o valor da LongDatePattern propriedade para algumas culturas.

using namespace System;
using namespace System::Globalization;
void PrintPattern( String^ myCulture )
{
   CultureInfo^ MyCI = gcnew CultureInfo( myCulture,false );
   DateTimeFormatInfo^ myDTFI = MyCI->DateTimeFormat;
   Console::WriteLine( " {0} {1}", myCulture, myDTFI->LongDatePattern );
}

int main()
{
   
   // Displays the values of the pattern properties.
   Console::WriteLine( " CULTURE    PROPERTY VALUE" );
   PrintPattern( "en-US" );
   PrintPattern( "ja-JP" );
   PrintPattern( "fr-FR" );
}

/*
This code produces the following output:

CULTURE    PROPERTY VALUE
en-US     dddd, MMMM dd, yyyy
ja-JP     yyyy'年'M'月'd'日'
fr-FR     dddd d MMMM yyyy

*/

using System;
using System.Globalization;

public class SamplesDTFI  {

   public static void Main()  {

      // Displays the values of the pattern properties.
      Console.WriteLine( " CULTURE    PROPERTY VALUE" );
      PrintPattern( "en-US" );
      PrintPattern( "ja-JP" );
      PrintPattern( "fr-FR" );
   }

   public static void PrintPattern( String myCulture )  {

      DateTimeFormatInfo myDTFI = new CultureInfo( myCulture, false ).DateTimeFormat;
      Console.WriteLine( "  {0}     {1}", myCulture, myDTFI.LongDatePattern );
   }
}

/*
This code produces the following output:

 CULTURE    PROPERTY VALUE
  en-US     dddd, MMMM d, yyyy
  ja-JP     yyyy'年'M'月'd'日'
  fr-FR     dddd d MMMM yyyy

*/

Imports System.Globalization

Public Class SamplesDTFI

   Public Shared Sub Main()

      ' Displays the values of the pattern properties.
      Console.WriteLine(" CULTURE    PROPERTY VALUE")
      PrintPattern("en-US")
      PrintPattern("ja-JP")
      PrintPattern("fr-FR")

   End Sub

   Public Shared Sub PrintPattern(myCulture As [String])

      Dim myDTFI As DateTimeFormatInfo = New CultureInfo(myCulture, False).DateTimeFormat
      Console.WriteLine("  {0}     {1}", myCulture, myDTFI.LongDatePattern)

   End Sub

End Class

'This code produces the following output:
'
' CULTURE    PROPERTY VALUE
'  en-US     dddd, MMMM d, yyyy
'  ja-JP     yyyy'年'M'月'd'日'
'  fr-FR     dddd d MMMM yyyy
'

Comentários

A LongDatePattern propriedade define o formato específico da cultura de cadeias de caracteres de data que são retornadas por chamadas para os DateTime.ToString métodos e DateTimeOffset.ToString e por cadeias de caracteres de formato composto que são fornecidas a cadeia de caracteres de formato padrão "D". O exemplo a seguir ilustra as relações entre as seguintes: a cadeia de caracteres de formato padrão "D", a cadeia de caracteres de formato personalizado retornada pela LongDatePattern propriedade e a representação específica da cultura de uma data.

using System;
using System.Globalization;

public class Example
{
   public static void Main()
   {
      DateTime date1 = new DateTime(2011, 11, 12);
      string[] cultureNames = { "en-US", "fr-FR", "ru-RU", "de-DE" };
      Console.WriteLine("{0,-7} {1,-20} {2:D}\n", "Culture", "Long Date Pattern", "Date");
      foreach (var cultureName in cultureNames) {
         CultureInfo culture = CultureInfo.CreateSpecificCulture(cultureName);
         Console.WriteLine("{0,-7} {1,-20} {2}",
                           culture.Name,
                           culture.DateTimeFormat.LongDatePattern,
                           date1.ToString("D", culture));
      }
   }
}
// The example displays the following output:
//    Culture Long Date Pattern    Date
//
//    en-US   dddd, MMMM d, yyyy   Saturday, November 12, 2011
//    fr-FR   dddd d MMMM yyyy     samedi 12 novembre 2011
//    ru-RU   d MMMM yyyy 'г.'     12 ноября 2011 г.
//    de-DE   dddd, d. MMMM yyyy   Samstag, 12. November 2011

Imports System.Globalization

Module Example
   Public Sub Main()
      Dim date1 As Date = #11/12/2011#
      Dim cultureNames() As String = { "en-US", "fr-FR", "ru-RU", "de-DE" }
      Console.WriteLine("{0,-7} {1,-20} {2:D}", "Culture", "Long Date Pattern", "Date")
      Console.WriteLine()
      For Each cultureName In cultureNames
         Dim culture As CultureInfo = CultureInfo.CreateSpecificCulture(cultureName)
         Console.WriteLine("{0,-7} {1,-20} {2}", culture.Name, culture.DateTimeFormat.LongDatePattern, 
                           date1.ToString("D", culture))                 
      Next
   End Sub
End Module
' The example displays the following output:
'    Culture Long Date Pattern    Date
'
'    en-US   dddd, MMMM d, yyyy   Saturday, November 12, 2011
'    fr-FR   dddd d MMMM yyyy     samedi 12 novembre 2011
'    ru-RU   d MMMM yyyy 'г.'     12 ноября 2011 г.
'    de-DE   dddd, d. MMMM yyyy   Samstag, 12. November 2011

Consulte Cadeias de caracteres de formato de data e hora personalizadas para especificadores de formato personalizado individuais que podem ser combinados para construir cadeias de caracteres de formato personalizado, como "dddd, dd MMMM aaaa".

Você deve definir o separador de data no padrão de data longa como uma cadeia de caracteres exata em vez de usar o espaço reservado separador de data. Por exemplo, para obter o padrão MM-DD-aaaa, defina o padrão de data longa como "MM-DD-aaaa".

O valor dessa propriedade poderá ser alterado se o calendário usado por uma cultura for alterado. Por exemplo, o exemplo a seguir mostra como a LongDatePattern propriedade de um CultureInfo objeto que representa a cultura árabe (Síria) muda quando o Calendar objeto usado pela cultura é alterado.

using System;
using System.Globalization;
using System.IO;

public class Example
{
   public static void Main()
   {
      DateTime date1 = new DateTime(2011, 8, 7);
      CultureInfo ci = CultureInfo.CreateSpecificCulture("ar-SY");
      StreamWriter sw = new StreamWriter(@".\arSYCalendars.txt");

      sw.WriteLine("{0,-32} {1,-21} {2}\n",
                   "Calendar", "Long Date Pattern", "Example Date");
      foreach (var cal in ci.OptionalCalendars) {
         ci.DateTimeFormat.Calendar = cal;
         sw.WriteLine("{0,-32} {1,-21} {2}", GetCalendarName(cal),
                                             ci.DateTimeFormat.LongDatePattern,
                                             date1.ToString("D", ci));
      }
      sw.Close();
   }

   private static string GetCalendarName(Calendar cal)
   {
      string calName;
      calName = cal.GetType().Name.Substring(0, cal.GetType().Name.IndexOf("Cal"));
      if (calName.Equals("Gregorian")) {
         GregorianCalendar grCal = cal as GregorianCalendar;
         calName += String.Format("-{0}", grCal.CalendarType);
      }
      return calName;
   }
}
// The example generates the following output:
//    Calendar                         Long Date Pattern     Example Date
//
//    Gregorian-Localized              dd MMMM, yyyy         07 آب, 2011
//    UmAlQura                         dd/MMMM/yyyy          07/رمضان/1432
//    Hijri                            dd MMMM, yyyy         08 رمضان, 1432
//    Gregorian-USEnglish              dddd, MMMM dd, yyyy   Sunday, August 07, 2011
//    Gregorian-MiddleEastFrench       dddd, MMMM dd, yyyy   dimanche, août 07, 2011
//    Gregorian-TransliteratedEnglish  dddd, MMMM dd, yyyy   الأحد, أغسطس 07, 2011
//    Gregorian-TransliteratedFrench   dddd, MMMM dd, yyyy   الأحد, أوت 07, 2011

Imports System.Globalization
Imports System.IO

Module Example
   Public Sub Main()
      Dim date1 As Date = #8/7/2011#
      Dim ci As CultureInfo = CultureInfo.CreateSpecificCulture("ar-SY")
      Dim sw As New StreamWriter(".\arSYCalendars.txt") 

      sw.WriteLine("{0,-32} {1,-21} {2}", 
                   "Calendar", "Long Date Pattern", "Example Date")
      sw.WriteLine()
      For Each cal As Calendar In ci.OptionalCalendars
         ci.DateTimeFormat.Calendar = cal
         sw.WriteLine("{0,-32} {1,-21} {2}", GetCalendarName(cal), 
                                             ci.DateTimeFormat.LongDatePattern,
                                             date1.ToString("D", ci))
      Next     
      sw.Close()
   End Sub
   
   Private Function GetCalendarName(cal As Calendar) As String
      Dim calName As String
      calName = cal.GetType().Name.Substring(0, cal.GetType().Name.IndexOf("Cal"))
      If calName.Equals("Gregorian") Then
         Dim grCal As GregorianCalendar = DirectCast(cal, GregorianCalendar)
         calName += String.Format("-{0}", grCal.CalendarType)    
      End If
      Return calName
   End Function
End Module
' The example generates the following output:
'    Calendar                         Long Date Pattern     Example Date
'    
'    Gregorian-Localized              dd MMMM, yyyy         07 آب, 2011
'    UmAlQura                         dd/MMMM/yyyy          07/رمضان/1432
'    Hijri                            dd MMMM, yyyy         08 رمضان, 1432
'    Gregorian-USEnglish              dddd, MMMM dd, yyyy   Sunday, August 07, 2011
'    Gregorian-MiddleEastFrench       dddd, MMMM dd, yyyy   dimanche, août 07, 2011
'    Gregorian-TransliteratedEnglish  dddd, MMMM dd, yyyy   الأحد, أغسطس 07, 2011
'    Gregorian-TransliteratedFrench   dddd, MMMM dd, yyyy   الأحد, أوت 07, 2011

Aplica-se a

Confira também