Enumerable.Min Method (IEnumerable<Double>)

Syntax

'Declaration
<ExtensionAttribute> _
Public Shared Function Min ( _
    source As IEnumerable(Of Double) _
) As Double

public static double Min(
    this IEnumerable<double> source
)

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Double>. When you use instance method syntax to call this method, omit the first parameter.

Exceptions

Remarks

The Min(IEnumerable<Double>) method uses the Double implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

Examples

The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

      ' Create an array of double values.
      Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

      ' Determine the smallest number in the array.
      Dim min As Double = doubles.Min()

      ' Display the result.
      outputBlock.Text &= "The smallest number is " & min & vbCrLf

      ' This code produces the following output:
      '
      ' The smallest number is -2E+103

      double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

      double min = doubles.Min();

      outputBlock.Text += String.Format("The smallest number is {0}.", min) + "\n";

      /*
       This code produces the following output:

       The smallest number is -2E+103.
      */

Version Information

Silverlight

Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

Platforms

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.

See Also

Reference