Int16.MinValue Champ
Définition
Important
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Représente la plus petite valeur possible de Int16. Ce champ est constant.
public: short MinValue = -32768;public const short MinValue = -32768;val mutable MinValue : int16Public Const MinValue As Short = -32768Valeur de champ
Value = -32768Exemples
L’exemple suivant utilise la MinValue propriété pour empêcher un lors de OverflowException la conversion en valeur Int16 .
array<Int64>^ numbersToConvert = {162345, 32183, -54000};
Int16 newNumber;
for each (Int64 number in numbersToConvert)
{
if (number >= Int16::MinValue && number <= Int16::MaxValue)
{
newNumber = Convert::ToInt16(number);
Console::WriteLine("Successfully converted {0} to an Int16.",
newNumber);
}
else
{
Console::WriteLine("Unable to convert {0} to an Int16.", number);
}
}
// The example displays the following output:
// Unable to convert 162345 to an Int16.
// Successfully converted 32183 to an Int16.
// Unable to convert -54000 to an Int16.
long[] numbersToConvert = {162345, 32183, -54000};
short newNumber;
foreach (long number in numbersToConvert)
{
if (number >= Int16.MinValue && number <= Int16.MaxValue)
{
newNumber = Convert.ToInt16(number);
Console.WriteLine($"Successfully converted {newNumber} to an Int16.");
}
else
{
Console.WriteLine($"Unable to convert {number} to an Int16.");
}
}
// The example displays the following output to the console:
// Unable to convert 162345 to an Int16.
// Successfully converted 32183 to an Int16.
// Unable to convert -54000 to an Int16.
open System
let numbersToConvert = [ 162345L; 32183L; -54000L ]
for number in numbersToConvert do
if number >= int64 Int16.MinValue && number <= int64 Int16.MaxValue then
let newNumber = Convert.ToInt16 number
printfn $"Successfully converted {newNumber} to an Int16."
else
printfn $"Unable to convert {number} to an Int16."
// The example displays the following output to the console:
// Unable to convert 162345 to an Int16.
// Successfully converted 32183 to an Int16.
// Unable to convert -54000 to an Int16.
Dim numbersToConvert() As Long = {162345, 32183, -54000}
Dim newNumber As Int16
For Each number As Long In NumbersToConvert
If number >= Int16.MinValue And number <= Int16.MaxValue Then
newNumber = Convert.ToInt16(number)
Console.WriteLine("Successfully converted {0} to an Int16.", _
newNumber)
Else
Console.WriteLine("Unable to convert {0} to an Int16.", number)
End If
Next
' The example displays the following output to the console:
' Unable to convert 162345 to an Int16.
' Successfully converted 32183 to an Int16.
' Unable to convert -54000 to an Int16.
Remarques
La valeur de cette constante est -32768 ; autrement dit, 0x8000 hexadécimaux.
La MinValue propriété est généralement utilisée pour empêcher un lors de la conversion d’un OverflowException type numérique avec une plage inférieure supérieure (par exemple, un Int32 ou un Int64) en .Int16 L’exemple illustre cette utilisation.
