String.Concat Metodo

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(System::String ^ str0, System::String ^ str1, System::String ^ str2, System::String ^ str3);

public static string Concat (string str0, string str1, string str2, string str3);

public static string Concat (string? str0, string? str1, string? str2, string? str3);

static member Concat : string * string * string * string -> string

Public Shared Function Concat (str0 As String, str1 As String, str2 As String, str3 As String) As String

Parametri

Restituisce

Concatenazione di str0, str1, str2e str3.

Esempio

Nell'esempio seguente viene definita una matrice di parole di quattro lettere e le singole lettere vengono archiviate in una matrice di stringhe per poterle sbattere. Chiama quindi il metodo Concat(String, String, String, String) per riassemblare le parole sbattete.

using System;
using System.Collections;

public class Example
{
   public static void Main()
   {
      const int WORD_SIZE = 4;
      
      // Define some 4-letter words to be scrambled.
      string[] words = { "home", "food", "game", "rest" };
      // Define two arrays equal to the number of letters in each word.
      double[] keys = new double[WORD_SIZE];
      string[] letters = new string[WORD_SIZE];
      // Initialize the random number generator.
      Random rnd = new Random();
      
      // Scramble each word.
      foreach (string word in words)
      {
         for (int ctr = 0; ctr < word.Length; ctr++)
         {
            // Populate the array of keys with random numbers.
            keys[ctr] = rnd.NextDouble();
            // Assign a letter to the array of letters.
            letters[ctr] = word[ctr].ToString();
         }   
         // Sort the array. 
         Array.Sort(keys, letters, 0, WORD_SIZE, Comparer.Default);      
         // Display the scrambled word.
         string scrambledWord = String.Concat(letters[0], letters[1], 
                                              letters[2], letters[3]);
         Console.WriteLine("{0} --> {1}", word, scrambledWord);
      } 
   }
}
// The example displays output like the following:
//       home --> mheo
//       food --> oodf
//       game --> aemg
//       rest --> trse

open System
open System.Collections

let WORD_SIZE = 4
      
// Define some 4-letter words to be scrambled.
let words = [| "home"; "food"; "game"; "rest" |]
// Define two arrays equal to the number of letters in each word.
let keys = Array.zeroCreate<float> WORD_SIZE
let letters = Array.zeroCreate<string> WORD_SIZE
// Initialize the random number generator.
let rnd = Random()

// Scramble each word.
for word in words do
    for i = 0 to word.Length - 1 do
        // Populate the array of keys with random numbers.
        keys[i] <- rnd.NextDouble()
        // Assign a letter to the array of letters.
        letters[i] <- string word[i]
    // Sort the array. 
    Array.Sort(keys, letters, 0, WORD_SIZE, Comparer.Default)      
    // Display the scrambled word.
    let scrambledWord = String.Concat(letters[0], letters[1], letters[2], letters[3])
    printfn $"{word} --> {scrambledWord}"
// The example displays output like the following:
//       home --> mheo
//       food --> oodf
//       game --> aemg
//       rest --> trse

Imports System.Collections

Module Example
   Public Sub Main()
      Const WORD_SIZE As Integer = 4
      
      ' Define some 4-letter words to be scrambled.
      Dim words() As String = { "home", "food", "game", "rest" }
      ' Define two arrays equal to the number of letters in each word.
      Dim keys(WORD_SIZE) As Double
      Dim letters(WORD_SIZE) As String
      ' Initialize the random number generator.
      Dim rnd As New Random()
      
      ' Scramble each word.
      For Each word As String In words
         For ctr As Integer = 0 To word.Length - 1
            ' Populate the array of keys with random numbers.
            keys(ctr) = rnd.NextDouble()
            ' Assign a letter to the array of letters.
            letters(ctr) = word.Chars(ctr)
         Next   
         ' Sort the array. 
         Array.Sort(keys, letters, 0, WORD_SIZE, Comparer.Default)      
         ' Display the scrambled word.
         Dim scrambledWord As String = String.Concat(letters(0), letters(1), _
                                                     letters(2), letters(3))
         Console.WriteLine("{0} --> {1}", word, scrambledWord)
      Next 
   End Sub
End Module 
' The example displays output like the following:
'       home --> mheo
'       food --> oodf
'       game --> aemg
'       rest --> trse

Commenti

Il metodo concatena str0, str1, str2e str3; non aggiunge alcun delimitatore.

Vedi anche

• Join(String, String[])

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(ReadOnlySpan<char> str0, ReadOnlySpan<char> str1, ReadOnlySpan<char> str2, ReadOnlySpan<char> str3);

public static string Concat (ReadOnlySpan<char> str0, ReadOnlySpan<char> str1, ReadOnlySpan<char> str2, ReadOnlySpan<char> str3);

static member Concat : ReadOnlySpan<char> * ReadOnlySpan<char> * ReadOnlySpan<char> * ReadOnlySpan<char> -> string

Public Shared Function Concat (str0 As ReadOnlySpan(Of Char), str1 As ReadOnlySpan(Of Char), str2 As ReadOnlySpan(Of Char), str3 As ReadOnlySpan(Of Char)) As String

Parametri

Restituisce

Rappresentazioni di stringa concatenate dei valori di str0, str1, str2 e str3.

public:
 static System::String ^ Concat(System::Object ^ arg0, System::Object ^ arg1, System::Object ^ arg2, System::Object ^ arg3);

[System.CLSCompliant(false)]
public static string Concat (object arg0, object arg1, object arg2, object arg3);

[<System.CLSCompliant(false)>]
static member Concat : obj * obj * obj * obj -> string

Public Shared Function Concat (arg0 As Object, arg1 As Object, arg2 As Object, arg3 As Object) As String

Parametri

Restituisce

Rappresentazione di stringa concatenata di ogni valore nell'elenco di parametri.

Attributi

CLSCompliantAttribute

Esempio

Nell'esempio seguente viene illustrato l'uso del metodo Concat(Object, Object, Object, Object) per concatenare un elenco di parametri di variabile. In questo caso, il metodo viene chiamato con nove parametri.

using System;
using System.Collections;

public class Example
{
   public static void Main()
   {
      const int WORD_SIZE = 4;
      
      // Define some 4-letter words to be scrambled.
      string[] words = { "home", "food", "game", "rest" };
      // Define two arrays equal to the number of letters in each word.
      double[] keys = new double[WORD_SIZE];
      string[] letters = new string[WORD_SIZE];
      // Initialize the random number generator.
      Random rnd = new Random();
      
      // Scramble each word.
      foreach (string word in words)
      {
         for (int ctr = 0; ctr < word.Length; ctr++)
         {
            // Populate the array of keys with random numbers.
            keys[ctr] = rnd.NextDouble();
            // Assign a letter to the array of letters.
            letters[ctr] = word[ctr].ToString();
         }   
         // Sort the array. 
         Array.Sort(keys, letters, 0, WORD_SIZE, Comparer.Default);      
         // Display the scrambled word.
         string scrambledWord = String.Concat(letters[0], letters[1], 
                                              letters[2], letters[3]);
         Console.WriteLine("{0} --> {1}", word, scrambledWord);
      } 
   }
}
// The example displays output like the following:
//       home --> mheo
//       food --> oodf
//       game --> aemg
//       rest --> trse

open System
open System.Collections

let WORD_SIZE = 4
      
// Define some 4-letter words to be scrambled.
let words = [| "home"; "food"; "game"; "rest" |]
// Define two arrays equal to the number of letters in each word.
let keys = Array.zeroCreate<float> WORD_SIZE
let letters = Array.zeroCreate<string> WORD_SIZE
// Initialize the random number generator.
let rnd = Random()

// Scramble each word.
for word in words do
    for i = 0 to word.Length - 1 do
        // Populate the array of keys with random numbers.
        keys[i] <- rnd.NextDouble()
        // Assign a letter to the array of letters.
        letters[i] <- string word[i]
    // Sort the array. 
    Array.Sort(keys, letters, 0, WORD_SIZE, Comparer.Default)      
    // Display the scrambled word.
    let scrambledWord = String.Concat(letters[0], letters[1], letters[2], letters[3])
    printfn $"{word} --> {scrambledWord}"
// The example displays output like the following:
//       home --> mheo
//       food --> oodf
//       game --> aemg
//       rest --> trse

Imports System.Collections

Module Example
   Public Sub Main()
      Const WORD_SIZE As Integer = 4
      
      ' Define some 4-letter words to be scrambled.
      Dim words() As String = { "home", "food", "game", "rest" }
      ' Define two arrays equal to the number of letters in each word.
      Dim keys(WORD_SIZE) As Double
      Dim letters(WORD_SIZE) As String
      ' Initialize the random number generator.
      Dim rnd As New Random()
      
      ' Scramble each word.
      For Each word As String In words
         For ctr As Integer = 0 To word.Length - 1
            ' Populate the array of keys with random numbers.
            keys(ctr) = rnd.NextDouble()
            ' Assign a letter to the array of letters.
            letters(ctr) = word.Chars(ctr)
         Next   
         ' Sort the array. 
         Array.Sort(keys, letters, 0, WORD_SIZE, Comparer.Default)      
         ' Display the scrambled word.
         Dim scrambledWord As String = String.Concat(letters(0), letters(1), _
                                                     letters(2), letters(3))
         Console.WriteLine("{0} --> {1}", word, scrambledWord)
      Next 
   End Sub
End Module 
' The example displays output like the following:
'       home --> mheo
'       food --> oodf
'       game --> aemg
'       rest --> trse

Commenti

Il metodo concatena ogni oggetto nell'elenco di parametri chiamando il metodo ToString senza parametri; non aggiunge alcun delimitatore.

String.Empty viene usato al posto di qualsiasi argomento Null.

Note per i chiamanti

Questo metodo è contrassegnato con la parola chiave vararg, il che significa che supporta un numero variabile di parametri. Il metodo può essere chiamato da Visual C++, ma non può essere chiamato dal codice C# o Visual Basic. I compilatori C# e Visual Basic risolvono le chiamate a Concat(Object, Object, Object, Object) come chiamate a Concat(Object[]).

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(System::String ^ str0, System::String ^ str1, System::String ^ str2);

public static string Concat (string str0, string str1, string str2);

public static string Concat (string? str0, string? str1, string? str2);

static member Concat : string * string * string -> string

Public Shared Function Concat (str0 As String, str1 As String, str2 As String) As String

Parametri

Restituisce

Concatenazione di str0, str1e str2.

Esempio

Nell'esempio seguente viene utilizzato il metodo Concat per concatenare tre stringhe e visualizzare il risultato.

using namespace System;

void main()
{
   String^ s1 = "We went to a bookstore, ";
   String^ s2 = "a movie, ";
   String^ s3 = "and a restaurant.";

   String^ s = String::Concat(s1, s2, s3);
   Console::WriteLine(s);
}
// The example displays the following output:
//      We went to a bookstore, a movie, and a restaurant.

using System;

public class Example
{
   public static void Main()
   {
      String s1 = "We went to a bookstore, ";
      String s2 = "a movie, ";
      String s3 = "and a restaurant.";

      var s = String.Concat(s1, s2, s3);
      Console.WriteLine(s);
   }
}
// The example displays the following output:
//      We went to a bookstore, a movie, and a restaurant.

open System

let s1 = "We went to a bookstore, "
let s2 = "a movie, "
let s3 = "and a restaurant."

String.Concat(s1, s2, s3)
|> printfn "%s"
// The example displays the following output:
//      We went to a bookstore, a movie, and a restaurant.

Public Module Example
   Public Sub Main()
      Dim s1 As String = "We went to a bookstore, "
      Dim s2 As String = "a movie, "
      Dim s3 As String = "and a restaurant."

      Dim s = String.Concat(s1, s2, s3)
      Console.WriteLine(s)
   End Sub
End Module
' The example displays the following output:
'      We went to a bookstore, a movie, and a restaurant.

Commenti

Il metodo concatena str0, str1e str2; non aggiunge alcun delimitatore.

Vedi anche

• Join(String, String[])

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(ReadOnlySpan<char> str0, ReadOnlySpan<char> str1, ReadOnlySpan<char> str2);

public static string Concat (ReadOnlySpan<char> str0, ReadOnlySpan<char> str1, ReadOnlySpan<char> str2);

static member Concat : ReadOnlySpan<char> * ReadOnlySpan<char> * ReadOnlySpan<char> -> string

Public Shared Function Concat (str0 As ReadOnlySpan(Of Char), str1 As ReadOnlySpan(Of Char), str2 As ReadOnlySpan(Of Char)) As String

Parametri

Restituisce

Rappresentazioni di stringa concatenate dei valori di str0, str1 e str2.

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(System::Object ^ arg0, System::Object ^ arg1, System::Object ^ arg2);

public static string Concat (object arg0, object arg1, object arg2);

public static string Concat (object? arg0, object? arg1, object? arg2);

static member Concat : obj * obj * obj -> string

Public Shared Function Concat (arg0 As Object, arg1 As Object, arg2 As Object) As String

Parametri

Restituisce

Rappresentazioni di stringa concatenate dei valori di arg0, arg1e arg2.

Esempio

Nell'esempio seguente viene illustrato il metodo Concat.

using namespace System;

int main()
{
   int i = -123;
   Object^ o = i;
   array<Object^>^objs = { -123, -456, -789};
   Console::WriteLine("Concatenate 1, 2, and 3 objects:");
   Console::WriteLine("1) {0}", String::Concat(o));
   Console::WriteLine("2) {0}", String::Concat(o, o));
   Console::WriteLine("3) {0}", String::Concat(o, o, o));
   
   Console::WriteLine("\nConcatenate 4 objects and a variable length parameter list:" );
   Console::WriteLine("4) {0}", String::Concat(o, o, o, o));
   Console::WriteLine("5) {0}", String::Concat( o, o, o, o, o));
   Console::WriteLine("\nConcatenate a 3-element object array:");
   Console::WriteLine("6) {0}", String::Concat(objs));
}
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//    
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//    
//    Concatenate a 3-element object array:
//    6) -123-456-789

using System;

class stringConcat5 {
    public static void Main() {
    int i = -123;
    Object o = i;
    Object[] objs = new Object[] {-123, -456, -789};

    Console.WriteLine("Concatenate 1, 2, and 3 objects:");
    Console.WriteLine("1) {0}", String.Concat(o));
    Console.WriteLine("2) {0}", String.Concat(o, o));
    Console.WriteLine("3) {0}", String.Concat(o, o, o));

    Console.WriteLine("\nConcatenate 4 objects and a variable length parameter list:");
    Console.WriteLine("4) {0}", String.Concat(o, o, o, o));
    Console.WriteLine("5) {0}", String.Concat(o, o, o, o, o));

    Console.WriteLine("\nConcatenate a 3-element object array:");
    Console.WriteLine("6) {0}", String.Concat(objs));
    }
}
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//
//    Concatenate a 3-element object array:
//    6) -123-456-789

open System

let i = -123
let o: obj = i
let objs: obj[] = [| -123; -456; -789 |]

printfn "Concatenate 1, 2, and 3 objects:"
printfn $"1) {String.Concat o}"
printfn $"2) {String.Concat(o, o)}"
printfn $"3) {String.Concat(o, o, o)}"

printfn "\nConcatenate 4 objects and a variable length parameter list:"
printfn $"4) {String.Concat(o, o, o, o)}"
printfn $"5) {String.Concat(o, o, o, o, o)}"

printfn "\nConcatenate a 3-element object array:"
printfn $"6) {String.Concat objs}" 
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//
//    Concatenate a 3-element object array:
//    6) -123-456-789

Class stringConcat5
   Public Shared Sub Main()
      Dim i As Integer = - 123
      Dim o As [Object] = i
      Dim objs() As [Object] = {-123, -456, -789}
      
      Console.WriteLine("Concatenate 1, 2, and 3 objects:")
      Console.WriteLine("1) {0}", [String].Concat(o))
      Console.WriteLine("2) {0}", [String].Concat(o, o))
      Console.WriteLine("3) {0}", [String].Concat(o, o, o))
      
      Console.WriteLine(vbCrLf & "Concatenate 4 objects and a variable length parameter list:")
      Console.WriteLine("4) {0}", String.Concat(o, o, o, o))
      Console.WriteLine("5) {0}", String.Concat(o, o, o, o, o))
      
      Console.WriteLine(vbCrLf & "Concatenate a 3-element object array:")
      Console.WriteLine("6) {0}", [String].Concat(objs))
   End Sub
End Class
'The example displays the following output:
'    Concatenate 1, 2, and 3 objects:
'    1) -123
'    2) -123-123
'    3) -123-123-123
'    
'    Concatenate 4 objects and a variable length parameter list:
'    4) -123-123-123-123
'    5) -123-123-123-123-123
'         
'    Concatenate a 3-element object array:
'    6) -123-456-789

Commenti

Il metodo concatena arg0, arg1e arg2 chiamando il metodo ToString senza parametri di ogni oggetto; non aggiunge alcun delimitatore.

String.Empty viene usato al posto di qualsiasi argomento Null.

Vedi anche

• Object
• Join(String, String[])

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(System::String ^ str0, System::String ^ str1);

public static string Concat (string str0, string str1);

public static string Concat (string? str0, string? str1);

static member Concat : string * string -> string

Public Shared Function Concat (str0 As String, str1 As String) As String

Parametri

Restituisce

Concatenazione di str0 e str1.

Esempio

Nell'esempio seguente viene concatenato il nome, il secondo e il cognome di una persona.

using namespace System;
int main()
{
   
   // we want to simply quickly add this person's name together
   String^ fName = "Simon";
   String^ mName = "Jake";
   String^ lName = "Harrows";
   
   // because we want a name to appear with a space in between each name, 
   // put a space on the front of the middle, and last name, allowing for
   // the fact that a space may already be there
   mName = String::Concat(  " ", mName->Trim() );
   lName = String::Concat(  " ", lName->Trim() );
   
   // this line simply concatenates the two strings
   Console::WriteLine( "Welcome to this page, '{0}'!", String::Concat( String::Concat( fName, mName ), lName ) );
}
// The example displays the following output:
//        Welcome to this page, 'Simon Jake Harrows'!

using System;

public class ConcatTest {
    public static void Main() {

        // we want to simply quickly add this person's name together
        string fName = "Simon";
        string mName = "Jake";
        string lName = "Harrows";

        // because we want a name to appear with a space in between each name,
        // put a space on the front of the middle, and last name, allowing for
        // the fact that a space may already be there
        mName = " " + mName.Trim();
        lName = " " + lName.Trim();

        // this line simply concatenates the two strings
        Console.WriteLine("Welcome to this page, '{0}'!", string.Concat( string.Concat(fName, mName), lName ) );
    }
}
// The example displays the following output:
//        Welcome to this page, 'Simon Jake Harrows'!

open System

[<EntryPoint>]
let main _ =
    // we want to simply quickly add this person's name together
    let fName = "Simon"
    let mName = "Jake"
    let lName = "Harrows"

    // because we want a name to appear with a space in between each name,
    // put a space on the front of the middle, and last name, allowing for
    // the fact that a space may already be there
    let mName = " " + mName.Trim()
    let lName = " " + lName.Trim()

    // this line simply concatenates the two strings
    printfn $"Welcome to this page, '{String.Concat(String.Concat(fName, mName), lName)}'!"
    0
// The example displays the following output:
//        Welcome to this page, 'Simon Jake Harrows'!

Public Class ConcatTest
    Public Shared Sub Main()
        Dim fName As String = "Simon"
        Dim mName As String = "Jake"
        Dim lName As String = "Harrows"
        
        ' We want to simply quickly add this person's name together.
        ' Because we want a name to appear with a space in between each name, 
        ' we put a space on the front of the middle, and last name, allowing for
        ' the fact that a space may already be there.
        mName = " " + mName.Trim()
        lName = " " + lName.Trim()
        
        ' This line simply concatenates the two strings.
        Console.WriteLine("Welcome to this page, '{0}'!", _
                          String.Concat(String.Concat(fName, mName), lName))
    End Sub
End Class
' The example displays the following output:
'       Welcome to this page, 'Simon Jake Harrows'!

Commenti

Il metodo concatena str0 e str1; non aggiunge alcun delimitatore.

Una stringa Empty viene usata al posto di qualsiasi argomento Null.

Vedi anche

• Join(String, String[])

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(System::Object ^ arg0);

public static string Concat (object arg0);

public static string Concat (object? arg0);

static member Concat : obj -> string

Public Shared Function Concat (arg0 As Object) As String

Parametri

Restituisce

Rappresentazione di stringa del valore di arg0o Empty se arg0 è null.

Esempio

Nell'esempio seguente viene illustrato il metodo Concat.

using namespace System;

int main()
{
   int i = -123;
   Object^ o = i;
   array<Object^>^objs = { -123, -456, -789};
   Console::WriteLine("Concatenate 1, 2, and 3 objects:");
   Console::WriteLine("1) {0}", String::Concat(o));
   Console::WriteLine("2) {0}", String::Concat(o, o));
   Console::WriteLine("3) {0}", String::Concat(o, o, o));
   
   Console::WriteLine("\nConcatenate 4 objects and a variable length parameter list:" );
   Console::WriteLine("4) {0}", String::Concat(o, o, o, o));
   Console::WriteLine("5) {0}", String::Concat( o, o, o, o, o));
   Console::WriteLine("\nConcatenate a 3-element object array:");
   Console::WriteLine("6) {0}", String::Concat(objs));
}
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//    
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//    
//    Concatenate a 3-element object array:
//    6) -123-456-789

using System;

class stringConcat5 {
    public static void Main() {
    int i = -123;
    Object o = i;
    Object[] objs = new Object[] {-123, -456, -789};

    Console.WriteLine("Concatenate 1, 2, and 3 objects:");
    Console.WriteLine("1) {0}", String.Concat(o));
    Console.WriteLine("2) {0}", String.Concat(o, o));
    Console.WriteLine("3) {0}", String.Concat(o, o, o));

    Console.WriteLine("\nConcatenate 4 objects and a variable length parameter list:");
    Console.WriteLine("4) {0}", String.Concat(o, o, o, o));
    Console.WriteLine("5) {0}", String.Concat(o, o, o, o, o));

    Console.WriteLine("\nConcatenate a 3-element object array:");
    Console.WriteLine("6) {0}", String.Concat(objs));
    }
}
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//
//    Concatenate a 3-element object array:
//    6) -123-456-789

open System

let i = -123
let o: obj = i
let objs: obj[] = [| -123; -456; -789 |]

printfn "Concatenate 1, 2, and 3 objects:"
printfn $"1) {String.Concat o}"
printfn $"2) {String.Concat(o, o)}"
printfn $"3) {String.Concat(o, o, o)}"

printfn "\nConcatenate 4 objects and a variable length parameter list:"
printfn $"4) {String.Concat(o, o, o, o)}"
printfn $"5) {String.Concat(o, o, o, o, o)}"

printfn "\nConcatenate a 3-element object array:"
printfn $"6) {String.Concat objs}" 
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//
//    Concatenate a 3-element object array:
//    6) -123-456-789

Class stringConcat5
   Public Shared Sub Main()
      Dim i As Integer = - 123
      Dim o As [Object] = i
      Dim objs() As [Object] = {-123, -456, -789}
      
      Console.WriteLine("Concatenate 1, 2, and 3 objects:")
      Console.WriteLine("1) {0}", [String].Concat(o))
      Console.WriteLine("2) {0}", [String].Concat(o, o))
      Console.WriteLine("3) {0}", [String].Concat(o, o, o))
      
      Console.WriteLine(vbCrLf & "Concatenate 4 objects and a variable length parameter list:")
      Console.WriteLine("4) {0}", String.Concat(o, o, o, o))
      Console.WriteLine("5) {0}", String.Concat(o, o, o, o, o))
      
      Console.WriteLine(vbCrLf & "Concatenate a 3-element object array:")
      Console.WriteLine("6) {0}", [String].Concat(objs))
   End Sub
End Class
'The example displays the following output:
'    Concatenate 1, 2, and 3 objects:
'    1) -123
'    2) -123-123
'    3) -123-123-123
'    
'    Concatenate 4 objects and a variable length parameter list:
'    4) -123-123-123-123
'    5) -123-123-123-123-123
'         
'    Concatenate a 3-element object array:
'    6) -123-456-789

Commenti

Il metodo Concat(Object) rappresenta arg0 come stringa chiamando il metodo ToString senza parametri.

Vedi anche

• Object
• Join(String, String[])

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(System::Object ^ arg0, System::Object ^ arg1);

public static string Concat (object arg0, object arg1);

public static string Concat (object? arg0, object? arg1);

static member Concat : obj * obj -> string

Public Shared Function Concat (arg0 As Object, arg1 As Object) As String

Parametri

Restituisce

Rappresentazioni di stringa concatenate dei valori di arg0 e arg1.

Esempio

Nell'esempio seguente viene illustrato il metodo Concat.

using namespace System;

int main()
{
   int i = -123;
   Object^ o = i;
   array<Object^>^objs = { -123, -456, -789};
   Console::WriteLine("Concatenate 1, 2, and 3 objects:");
   Console::WriteLine("1) {0}", String::Concat(o));
   Console::WriteLine("2) {0}", String::Concat(o, o));
   Console::WriteLine("3) {0}", String::Concat(o, o, o));
   
   Console::WriteLine("\nConcatenate 4 objects and a variable length parameter list:" );
   Console::WriteLine("4) {0}", String::Concat(o, o, o, o));
   Console::WriteLine("5) {0}", String::Concat( o, o, o, o, o));
   Console::WriteLine("\nConcatenate a 3-element object array:");
   Console::WriteLine("6) {0}", String::Concat(objs));
}
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//    
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//    
//    Concatenate a 3-element object array:
//    6) -123-456-789

using System;

class stringConcat5 {
    public static void Main() {
    int i = -123;
    Object o = i;
    Object[] objs = new Object[] {-123, -456, -789};

    Console.WriteLine("Concatenate 1, 2, and 3 objects:");
    Console.WriteLine("1) {0}", String.Concat(o));
    Console.WriteLine("2) {0}", String.Concat(o, o));
    Console.WriteLine("3) {0}", String.Concat(o, o, o));

    Console.WriteLine("\nConcatenate 4 objects and a variable length parameter list:");
    Console.WriteLine("4) {0}", String.Concat(o, o, o, o));
    Console.WriteLine("5) {0}", String.Concat(o, o, o, o, o));

    Console.WriteLine("\nConcatenate a 3-element object array:");
    Console.WriteLine("6) {0}", String.Concat(objs));
    }
}
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//
//    Concatenate a 3-element object array:
//    6) -123-456-789

open System

let i = -123
let o: obj = i
let objs: obj[] = [| -123; -456; -789 |]

printfn "Concatenate 1, 2, and 3 objects:"
printfn $"1) {String.Concat o}"
printfn $"2) {String.Concat(o, o)}"
printfn $"3) {String.Concat(o, o, o)}"

printfn "\nConcatenate 4 objects and a variable length parameter list:"
printfn $"4) {String.Concat(o, o, o, o)}"
printfn $"5) {String.Concat(o, o, o, o, o)}"

printfn "\nConcatenate a 3-element object array:"
printfn $"6) {String.Concat objs}" 
// The example displays the following output:
//    Concatenate 1, 2, and 3 objects:
//    1) -123
//    2) -123-123
//    3) -123-123-123
//
//    Concatenate 4 objects and a variable length parameter list:
//    4) -123-123-123-123
//    5) -123-123-123-123-123
//
//    Concatenate a 3-element object array:
//    6) -123-456-789

Class stringConcat5
   Public Shared Sub Main()
      Dim i As Integer = - 123
      Dim o As [Object] = i
      Dim objs() As [Object] = {-123, -456, -789}
      
      Console.WriteLine("Concatenate 1, 2, and 3 objects:")
      Console.WriteLine("1) {0}", [String].Concat(o))
      Console.WriteLine("2) {0}", [String].Concat(o, o))
      Console.WriteLine("3) {0}", [String].Concat(o, o, o))
      
      Console.WriteLine(vbCrLf & "Concatenate 4 objects and a variable length parameter list:")
      Console.WriteLine("4) {0}", String.Concat(o, o, o, o))
      Console.WriteLine("5) {0}", String.Concat(o, o, o, o, o))
      
      Console.WriteLine(vbCrLf & "Concatenate a 3-element object array:")
      Console.WriteLine("6) {0}", [String].Concat(objs))
   End Sub
End Class
'The example displays the following output:
'    Concatenate 1, 2, and 3 objects:
'    1) -123
'    2) -123-123
'    3) -123-123-123
'    
'    Concatenate 4 objects and a variable length parameter list:
'    4) -123-123-123-123
'    5) -123-123-123-123-123
'         
'    Concatenate a 3-element object array:
'    6) -123-456-789

Commenti

Il metodo concatena arg0 e arg1 chiamando il metodo ToString senza parametri di arg0 e arg1; non aggiunge alcun delimitatore.

String.Empty viene usato al posto di qualsiasi argomento Null.

Se uno degli argomenti è un riferimento alla matrice, il metodo concatena una stringa che rappresenta tale matrice anziché i relativi membri, ad esempio "System.String[]").

Vedi anche

• Object
• Join(String, String[])

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(... cli::array <System::String ^> ^ values);

public static string Concat (params string[] values);

public static string Concat (params string?[] values);

[System.CLSCompliant(false)]
public static string Concat (params string[] values);

static member Concat : string[] -> string

[<System.CLSCompliant(false)>]
static member Concat : string[] -> string

Public Shared Function Concat (ParamArray values As String()) As String

Parametri

Restituisce

Elementi concatenati di values.

Attributi

CLSCompliantAttribute

Eccezioni

Esempio

Nell'esempio seguente viene illustrato l'uso del metodo Concat con una matrice di String.

using namespace System;

int main()
{
   
   // Make an array of strings. Note that we have included spaces.
   array<String^>^s = { "hello ", "and ", "welcome ", "to ",
                        "this ", "demo! "};
   
   // Put all the strings together.
   Console::WriteLine( String::Concat(s) );
   
   // Sort the strings, and put them together.
   Array::Sort( s );
   Console::WriteLine( String::Concat(s));
}
// The example displays the following output:
//       hello and welcome to this demo!
//       and demo! hello this to welcome

using System;

public class Example
{
    public static void Main()
    {
        // Make an array of strings. Note that we have included spaces.
        string [] s = { "hello ", "and ", "welcome ", "to ",
                        "this ", "demo! " };

        // Put all the strings together.
        Console.WriteLine(string.Concat(s));

        // Sort the strings, and put them together.
        Array.Sort(s);
        Console.WriteLine(string.Concat(s));
    }
}
// The example displays the following output:
//       hello and welcome to this demo!
//       and demo! hello this to welcome

open System

// Make an array of strings. Note that we have included spaces.
let s = 
    [| "hello "; "and "; "welcome "; "to "
       "this "; "demo! " |]

// Put all the strings together.
printfn $"{String.Concat s}"

// Sort the strings, and put them together.
Array.Sort s
printfn $"{String.Concat s}"
// The example displays the following output:
//       hello and welcome to this demo!
//       and demo! hello this to welcome

Public Class Example
    Public Shared Sub Main()
        ' Make an array of strings. Note that we have included spaces.
        Dim s As String() = { "hello ", "and ", "welcome ", "to ",
                              "this ", "demo! "}

        ' Put all the strings together.
        Console.WriteLine(String.Concat(s))
        
        ' Sort the strings, and put them together.
        Array.Sort(s)
        Console.WriteLine(String.Concat(s))
    End Sub
End Class
' The example displays the following output:
'       hello and welcome to this demo!
'       and demo! hello this to welcome

Commenti

Il metodo concatena ogni oggetto in values; non aggiunge alcun delimitatore.

Una stringa Empty viene usata al posto di qualsiasi oggetto Null nella matrice.

Vedi anche

• Join(String, String[])

public:
 static System::String ^ Concat(ReadOnlySpan<System::String ^> values);

public static string Concat (scoped ReadOnlySpan<string?> values);

static member Concat : ReadOnlySpan<string> -> string

Public Shared Function Concat (values As ReadOnlySpan(Of String)) As String

Parametri

Restituisce

Elementi concatenati di values.

public:
 static System::String ^ Concat(ReadOnlySpan<System::Object ^> args);

public static string Concat (scoped ReadOnlySpan<object?> args);

static member Concat : ReadOnlySpan<obj> -> string

Public Shared Function Concat (args As ReadOnlySpan(Of Object)) As String

Parametri

Restituisce

Rappresentazioni di stringa concatenate dei valori degli elementi in args.

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(... cli::array <System::Object ^> ^ args);

public static string Concat (params object[] args);

public static string Concat (params object?[] args);

static member Concat : obj[] -> string

Public Shared Function Concat (ParamArray args As Object()) As String

Parametri

Restituisce

Rappresentazioni di stringa concatenate dei valori degli elementi in args.

Eccezioni

Esempio

Nell'esempio seguente viene illustrato l'uso del metodo Concat con una matrice di Object.

using System;

public class ConcatTest {
    public static void Main() {
        // Create a group of objects.
        Test1 t1 = new Test1();
        Test2 t2 = new Test2();
        int i = 16;
        string s = "Demonstration";

        // Place the objects in an array.
        object [] o = { t1, i, t2, s };

        // Concatenate the objects together as a string. To do this,
        // the ToString method of each of the objects is called.
        Console.WriteLine(string.Concat(o));
    }
}

// Create two empty test classes.
class Test1 {
}

class Test2 {
}
// The example displays the following output:
//       Test116Test2Demonstration

open System

// Create two empty test classes.
type Test1() = class end

type Test2() = class end

// Create a group of objects.
let t1 = new Test1()
let t2 = new Test2()
let i = 16
let s = "Demonstration"

// Place the objects in an array.
let o: obj[] = [| t1; i; t2; s |]

// Concatenate the objects together as a string. To do this,
// the ToString method of each of the objects is called.
printfn $"{String.Concat o}"

// The example displays the following output:
//       Test116Test2Demonstration

Public Class ConcatTest
    
    Public Shared Sub Main()
        Dim t1 As New Test1()
        Dim t2 As New Test2()
        Dim i As Integer = 16
        Dim s As String = "Demonstration"
        Dim o As Object() = {t1, i, t2, s}
        
        ' create a group of objects
        
        ' place the objects in an array
        
        ' concatenate the objects together as a string. To do this,
        ' the ToString method in the objects is called
        Console.WriteLine(String.Concat(o))
    End Sub
End Class


' imagine these test classes are full-fledged objects...
Class Test1
End Class

Class Test2
End Class

Commenti

Il metodo concatena ogni oggetto in args chiamando il metodo ToString senza parametri di tale oggetto; non aggiunge alcun delimitatore.

String.Empty viene usato al posto di qualsiasi oggetto Null nella matrice.

Note per i chiamanti

Questo metodo non viene chiamato dal codice C++. Il compilatore C++ risolve le chiamate a Concat con quattro o più parametri oggetto come chiamata a Concat(Object, Object, Object, Object).

Vedi anche

• Object
• Join(String, String[])

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(System::Collections::Generic::IEnumerable<System::String ^> ^ values);

public static string Concat (System.Collections.Generic.IEnumerable<string> values);

public static string Concat (System.Collections.Generic.IEnumerable<string?> values);

[System.Runtime.InteropServices.ComVisible(false)]
public static string Concat (System.Collections.Generic.IEnumerable<string> values);

static member Concat : seq<string> -> string

[<System.Runtime.InteropServices.ComVisible(false)>]
static member Concat : seq<string> -> string

Public Shared Function Concat (values As IEnumerable(Of String)) As String

Parametri

Restituisce

Le stringhe concatenate in valueso Empty se values è un IEnumerable(Of String)vuoto.

Attributi

ComVisibleAttribute

Eccezioni

Esempio

Nell'esempio seguente viene usato l'algoritmo Sieve di Eratosthenes per calcolare i numeri primi minori o uguali a 100. Assegna il risultato a un oggetto List<T> di tipo String, che passa quindi al metodo Concat(IEnumerable<String>).

using System;
using System.Collections.Generic;

public class Example
{
   public static void Main()
   {
      int maxPrime = 100;
      IEnumerable<String> primeList = GetPrimes(maxPrime);
      Console.WriteLine("Primes less than {0}:", maxPrime);
      Console.WriteLine("   {0}", String.Concat(primeList));
   }

   private static IEnumerable<String> GetPrimes(int maxPrime)
   {
      Array values = Array.CreateInstance(typeof(int), 
                              new int[] { maxPrime - 1}, new int[] { 2 }); 
      // Use Sieve of Erathsthenes to determine prime numbers.
      for (int ctr = values.GetLowerBound(0); ctr <= (int) Math.Ceiling(Math.Sqrt(values.GetUpperBound(0))); ctr++)
      {
                           
         if ((int) values.GetValue(ctr) == 1) continue;
         
         for (int multiplier = ctr; multiplier <=  maxPrime / 2; multiplier++)
            if (ctr * multiplier <= maxPrime)
               values.SetValue(1, ctr * multiplier);
      }      
      
      List<String> primes = new List<String>();
      for (int ctr = values.GetLowerBound(0); ctr <= values.GetUpperBound(0); ctr++)
         if ((int) values.GetValue(ctr) == 0) 
            primes.Add(ctr.ToString() + " ");
      return primes;
   }   
}
// The example displays the following output:
//    Primes less than 100:
//       2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97

open System

let getPrimes maxPrime =
    let values = Array.CreateInstance(typeof<int>, [| maxPrime - 1|], [| 2 |]) 
    // Use Sieve of Erathsthenes to determine prime numbers.
    for i = values.GetLowerBound 0 to values.GetUpperBound 0 |> float |> sqrt |> ceil |> int do
        if values.GetValue i :?> int <> 1 then
            for multiplier = i to maxPrime / 2 do
                if i * multiplier <= maxPrime then
                    values.SetValue(1, i * multiplier)
    seq {
        for i = values.GetLowerBound 0 to values.GetUpperBound 0 do
            if values.GetValue i :?> int = 0 then
                string i + " "
    }    

let maxPrime = 100
let primeList = getPrimes maxPrime
printfn $"Primes less than {maxPrime}:"
printfn $"   {String.Concat primeList}"

// The example displays the following output:
//    Primes less than 100:
//       2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97

Imports System.Collections.Generic

Module Example
   Public Sub Main()
      Dim maxPrime As Integer = 100
      Dim primeList As IEnumerable(Of String) = GetPrimes(maxPrime)
      Console.WriteLine("Primes less than {0}:", maxPrime)
      Console.WriteLine("   {0}", String.Concat(primeList))
   End Sub
   
   Private Function GetPrimes(maxPrime As Integer) As IEnumerable(Of String)
      Dim values As Array = Array.CreateInstance(GetType(Integer), _
                              New Integer() { maxPrime - 1}, New Integer(){ 2 }) 
      ' Use Sieve of Erathsthenes to determine prime numbers.
      For ctr As Integer = values.GetLowerBound(0) To _
                           CInt(Math.Ceiling(Math.Sqrt(values.GetUpperBound(0))))
         If CInt(values.GetValue(ctr)) = 1 Then Continue For
         
         For multiplier As Integer = ctr To maxPrime \ 2
            If ctr * multiplier <= maxPrime Then values.SetValue(1, ctr * multiplier)
         Next   
      Next      
      
      Dim primes As New List(Of String)
      For ctr As Integer = values.GetLowerBound(0) To values.GetUpperBound(0)
         If CInt(values.GetValue(ctr)) = 0 Then primes.Add(ctr.ToString() + " ")
      Next            
      Return primes
   End Function   
End Module
' The example displays the following output:
'    Primes less than 100:
'       2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97

Commenti

Il metodo concatena ogni oggetto in values; non aggiunge alcun delimitatore. Per specificare un delimitatore tra ogni membro di values, chiamare il metodo Join(String, IEnumerable<String>).

Una stringa Empty viene usata al posto di qualsiasi elemento Null in values.

Se values è un IEnumerable(Of String)vuoto, il metodo restituisce String.Empty. Se values è null, il metodo genera un'eccezione ArgumentNullException.

Concat(IEnumerable<String>) è un metodo pratico che consente di concatenare ogni elemento in una raccolta IEnumerable(Of String) senza prima convertire gli elementi in una matrice di stringhe. È particolarmente utile con le espressioni di query LINQ (Language-Integrated Query). Nell'esempio seguente viene passato un oggetto List(Of String) contenente le lettere maiuscole o minuscole dell'alfabeto a un'espressione lambda che seleziona lettere uguali o maggiori di una determinata lettera (che, nell'esempio, è "M"). L'insieme IEnumerable(Of String) restituito dal metodo Enumerable.Where viene passato al metodo Concat(IEnumerable<String>) per visualizzare il risultato come una singola stringa.

using System;
using System.Collections.Generic;
using System.Linq;

public class Example
{
   public static void Main()
   {
      string output = String.Concat( GetAlphabet(true).Where( letter => 
                      letter.CompareTo("M") >= 0));
      Console.WriteLine(output);  
   }

   private static List<string> GetAlphabet(bool upper)
   {
      List<string> alphabet = new List<string>();
      int charValue = upper ? 65 : 97;
      for (int ctr = 0; ctr <= 25; ctr++)
         alphabet.Add(((char)(charValue + ctr)).ToString());
      return alphabet; 
   }
}
// The example displays the following output:
//      MNOPQRSTUVWXYZ

// This example uses the F# Seq.filter function instead of Linq.
open System

let getAlphabet upper =
    let charValue = if upper then 65 else 97
    seq {
        for i = 0 to 25 do
            charValue + i |> char |> string
    }

getAlphabet true
|> Seq.filter (fun letter -> letter.CompareTo "M" >= 0)
|> String.Concat
|> printfn "%s"
// The example displays the following output:
//      MNOPQRSTUVWXYZ

Imports System.Collections.Generic
Imports System.Linq

Module modMain
   Public Sub Main()
      Dim output As String = String.Concat(GetAlphabet(true).Where(Function(letter) _
                                                         letter >= "M"))
        
      Console.WriteLine(output)                                     
   End Sub
   
   Private Function GetAlphabet(upper As Boolean) As List(Of String)
      Dim alphabet As New List(Of String)
      Dim charValue As Integer = CInt(IIf(upper, 65, 97))
      For ctr As Integer = 0 To 25
         alphabet.Add(ChrW(charValue + ctr).ToString())
      Next
      Return alphabet 
   End Function
End Module
' The example displays the following output:
'       MNOPQRSTUVWXYZ

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
 static System::String ^ Concat(ReadOnlySpan<char> str0, ReadOnlySpan<char> str1);

public static string Concat (ReadOnlySpan<char> str0, ReadOnlySpan<char> str1);

static member Concat : ReadOnlySpan<char> * ReadOnlySpan<char> -> string

Public Shared Function Concat (str0 As ReadOnlySpan(Of Char), str1 As ReadOnlySpan(Of Char)) As String

Parametri

Restituisce

Rappresentazioni di stringa concatenate dei valori di str0 e str1.

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

Origine:

String.Manipulation.cs

public:
generic <typename T>
 static System::String ^ Concat(System::Collections::Generic::IEnumerable<T> ^ values);

public static string Concat<T> (System.Collections.Generic.IEnumerable<T> values);

[System.Runtime.InteropServices.ComVisible(false)]
public static string Concat<T> (System.Collections.Generic.IEnumerable<T> values);

static member Concat : seq<'T> -> string

[<System.Runtime.InteropServices.ComVisible(false)>]
static member Concat : seq<'T> -> string

Public Shared Function Concat(Of T) (values As IEnumerable(Of T)) As String

Parametri di tipo

Parametri

Restituisce

Membri concatenati in values.

Attributi

ComVisibleAttribute

Eccezioni

Esempio

Nell'esempio seguente viene definita una classe Animal molto semplice che contiene il nome di un animale e l'ordine a cui appartiene. Definisce quindi un oggetto List<T> per contenere un numero di oggetti Animal. Viene chiamato il metodo di estensione Enumerable.Where per estrarre gli oggetti Animal la cui proprietà di Order è uguale a "Dro". Il risultato viene passato al metodo Concat<T>(IEnumerable<T>) e visualizzato alla console.

using System;
using System.Collections.Generic;
using System.Linq;

public class Animal
{
   public string Kind;
   public string Order;
   
   public Animal(string kind, string order)
   {
      this.Kind = kind;
      this.Order = order;
   }
   
   public override string ToString()
   {
      return this.Kind;
   }
}

public class Example
{
   public static void Main()
   {
      List<Animal> animals = new List<Animal>();
      animals.Add(new Animal("Squirrel", "Rodent"));
      animals.Add(new Animal("Gray Wolf", "Carnivora"));
      animals.Add(new Animal("Capybara", "Rodent"));
      string output = String.Concat(animals.Where( animal => 
                      (animal.Order == "Rodent")));
      Console.WriteLine(output);  
   }
}
// The example displays the following output:
//      SquirrelCapybara

// This example uses the F# Seq.filter function instead of Linq.
open System

type Animal =
  { Kind: string
    Order: string }
    override this.ToString() =
       this.Kind

let animals = ResizeArray()
animals.Add { Kind = "Squirrel"; Order = "Rodent" }
animals.Add { Kind = "Gray Wolf"; Order = "Carnivora" }
animals.Add { Kind = "Capybara"; Order = "Rodent" }

Seq.filter (fun animal -> animal.Order = "Rodent")
|> String.Concat
|> printfn "%s"
// The example displays the following output:
//      SquirrelCapybara

Imports System.Collections.Generic

Public Class Animal
   Public Kind As String
   Public Order As String
   
   Public Sub New(kind As String, order As String)
      Me.Kind = kind
      Me.Order = order
   End Sub
   
   Public Overrides Function ToString() As String
      Return Me.Kind
   End Function
End Class

Module Example
   Public Sub Main()
      Dim animals As New List(Of Animal)
      animals.Add(New Animal("Squirrel", "Rodent"))
      animals.Add(New Animal("Gray Wolf", "Carnivora"))
      animals.Add(New Animal("Capybara", "Rodent")) 
      Dim output As String = String.Concat(animals.Where(Function(animal) _
                                           animal.Order = "Rodent"))
      Console.WriteLine(output)                                           
   End Sub
End Module
' The example displays the following output:
'      SquirrelCapybara

Commenti

Il metodo concatena ogni oggetto in values; non aggiunge alcun delimitatore.

Una stringa Empty viene usata al posto di qualsiasi argomento Null.

Concat<T>(IEnumerable<T>) è un metodo pratico che consente di concatenare ogni elemento in una raccolta IEnumerable<T> senza prima convertire gli elementi in stringhe. È particolarmente utile con le espressioni di query LINQ (Query) Language-Integrated, come illustrato nell'esempio. La rappresentazione di stringa di ogni oggetto nell'insieme IEnumerable<T> viene derivata chiamando il metodo ToString dell'oggetto.