SemaphoreFullException Classe

Definição

public ref class SemaphoreFullException : Exception

public ref class SemaphoreFullException : SystemException

public class SemaphoreFullException : Exception

public class SemaphoreFullException : SystemException

[System.Runtime.InteropServices.ComVisible(false)]
[System.Serializable]
public class SemaphoreFullException : SystemException

type SemaphoreFullException = class
    inherit Exception

type SemaphoreFullException = class
    inherit SystemException

[<System.Runtime.InteropServices.ComVisible(false)>]
[<System.Serializable>]
type SemaphoreFullException = class
    inherit SystemException

Public Class SemaphoreFullException
Inherits Exception

Public Class SemaphoreFullException
Inherits SystemException

Herança

Object

Exception

SemaphoreFullException

Herança

Object

Exception

SystemException

SemaphoreFullException

Atributos

ComVisibleAttribute SerializableAttribute

Exemplos

O exemplo de código a seguir mostra como um erro de programação em um thread pode levar a um SemaphoreFullException em outro thread: dois threads entram em um semáforo. O segundo thread libera o semáforo duas vezes, enquanto o primeiro thread ainda está executando sua tarefa. Quando o primeiro thread é concluído e libera o semáforo, a contagem de semáforos já está cheia e uma exceção é gerada.

#using <System.dll>
using namespace System;
using namespace System::Threading;

public ref class Example
{
private:
   // A semaphore that can satisfy at most two concurrent
   // requests.
   //
   static Semaphore^ _pool = gcnew Semaphore( 2,2 );

public:
   static void main()
   {
      // Create and start two threads, A and B.
      //
      Thread^ tA = gcnew Thread( gcnew ThreadStart( ThreadA ) );
      tA->Start();

      Thread^ tB = gcnew Thread( gcnew ThreadStart( ThreadB ) );
      tB->Start();
   }

private:
   static void ThreadA()
   {
      // Thread A enters the semaphore and simulates a task
      // that lasts a second.
      //
      _pool->WaitOne();
      Console::WriteLine( L"Thread A entered the semaphore." );

      Thread::Sleep( 1000 );

      try
      {
         _pool->Release();
         Console::WriteLine( L"Thread A released the semaphore." );
      }
      catch ( Exception^ ex ) 
      {
         Console::WriteLine( L"Thread A: {0}", ex->Message );
      }
   }

   static void ThreadB()
   {
      // Thread B simulates a task that lasts half a second,
      // then enters the semaphore.
      //
      Thread::Sleep( 500 );

      _pool->WaitOne();
      Console::WriteLine( L"Thread B entered the semaphore." );
      
      // Due to a programming error, Thread B releases the
      // semaphore twice. To fix the program, delete one line.
      _pool->Release();
      _pool->Release();
      Console::WriteLine( L"Thread B exits successfully." );
   }
};
/* This code example produces the following output:

Thread A entered the semaphore.
Thread B entered the semaphore.
Thread B exits successfully.
Thread A: Adding the given count to the semaphore would cause it to exceed its maximum count.
 */

using System;
using System.Threading;

public class Example
{
    // A semaphore that can satisfy at most two concurrent
    // requests.
    //
    private static Semaphore _pool = new Semaphore(2, 2);

    public static void Main()
    {
        // Create and start two threads, A and B. 
        //
        Thread tA = new Thread(new ThreadStart(ThreadA));
        tA.Start();

        Thread tB = new Thread(new ThreadStart(ThreadB));
        tB.Start();
    }

    private static void ThreadA()
    {
        // Thread A enters the semaphore and simulates a task
        // that lasts a second.
        //
        _pool.WaitOne();
        Console.WriteLine("Thread A entered the semaphore.");

        Thread.Sleep(1000);

        try
        {
            _pool.Release();
            Console.WriteLine("Thread A released the semaphore.");
        }
        catch(Exception ex)
        {
            Console.WriteLine("Thread A: {0}", ex.Message);
        }
    }

    private static void ThreadB()
    {
        // Thread B simulates a task that lasts half a second,
        // then enters the semaphore.
        //
        Thread.Sleep(500);

        _pool.WaitOne();
        Console.WriteLine("Thread B entered the semaphore.");
        
        // Due to a programming error, Thread B releases the
        // semaphore twice. To fix the program, delete one line.
        _pool.Release();
        _pool.Release();
        Console.WriteLine("Thread B exits successfully.");
    }
}
/* This code example produces the following output:

Thread A entered the semaphore.
Thread B entered the semaphore.
Thread B exits successfully.
Thread A: Adding the given count to the semaphore would cause it to exceed its maximum count.
 */

Imports System.Threading

Public Class Example

    ' A semaphore that can satisfy at most two concurrent
    ' requests.
    '
    Private Shared _pool As New Semaphore(2, 2)

    <MTAThread> _
    Public Shared Sub Main()
        ' Create and start two threads, A and B. 
        '
        Dim tA As New Thread(AddressOf ThreadA)
        tA.Start()

        Dim tB As New Thread(AddressOf ThreadB)
        tB.Start()

    End Sub

    Private Shared Sub ThreadA()
        ' Thread A enters the semaphore and simulates a task
        ' that lasts a second.
        '
        _pool.WaitOne()
        Console.WriteLine("Thread A entered the semaphore.")

        Thread.Sleep(1000)

        Try
            _pool.Release()
            Console.WriteLine("Thread A released the semaphore.")
        Catch ex As Exception
            Console.WriteLine("Thread A: {0}", ex.Message)
        End Try
    End Sub

    Private Shared Sub ThreadB()
        ' Thread B simulates a task that lasts half a second,
        ' then enters the semaphore.
        '
        Thread.Sleep(500)

        _pool.WaitOne()
        Console.WriteLine("Thread B entered the semaphore.")
        
        ' Due to a programming error, Thread B releases the
        ' semaphore twice. To fix the program, delete one line.
        _pool.Release()
        _pool.Release()
        Console.WriteLine("Thread B exits successfully.")
    End Sub
End Class
' This code example produces the following output:
'
' Thread A entered the semaphore.
' Thread B entered the semaphore.
' Thread B exits successfully.
' Thread A: Adding the given count to the semaphore would cause it to exceed its maximum count.
'

Comentários

A contagem em um semáforo é decrementada sempre que um thread entra no semáforo e incrementado quando um thread libera o semáforo. Quando a contagem for zero, as solicitações subsequentes serão bloqueadas até que outros threads liberem o semáforo. Quando todos os threads liberam o semáforo, a contagem está no valor máximo especificado quando o semáforo foi criado. Se um erro de programação fizer com que um thread chame o Semaphore.Release método neste ponto, um SemaphoreFullException será gerado.

SemaphoreFullException não indica necessariamente um problema com o código em que a exceção ocorreu. Considere o cenário a seguir: Thread A e thread B insira um semáforo que tenha uma contagem máxima de dois. Um erro de programação no thread B faz com que ele chame Release duas vezes, para que a contagem no semáforo esteja cheia. Como resultado, quando o thread A eventualmente chama Release, um SemaphoreFullException é gerado.

Para obter uma lista de valores de propriedade iniciais para uma instância da SemaphoreFullException classe , consulte o SemaphoreFullException() construtor .

Construtores

Propriedades

Métodos

Eventos

Aplica-se a

Confira também

• Semaphore
• Sinal