ZipPackage Класс

Определение

public ref class ZipPackage sealed : System::IO::Packaging::Package

public sealed class ZipPackage : System.IO.Packaging.Package

type ZipPackage = class
    inherit Package

Public NotInheritable Class ZipPackage
Inherits Package

Наследование

Object

Package

ZipPackage

Примеры

В этом примере показано, как создать базовый ZipPackage.

В примере создается пакет, содержащий одну часть документа, определяемую как корневой элемент пакета на уровне PackageRelationshipпакета .

Пакет также содержит часть изображения и секунду PackageRelationship , которая определяет связь между частью исходного документа и целевой частью изображения. (Изображение — это ресурс, используемый с документом.)

//  -------------------------- CreatePackage --------------------------
/// <summary>
///   Creates a package zip file containing specified
///   content and resource files.</summary>
private static void CreatePackage()
{
    // Convert system path and file names to Part URIs. In this example
    // Uri partUriDocument /* /Content/Document.xml */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Content\Document.xml", UriKind.Relative));
    // Uri partUriResource /* /Resources/Image1.jpg */ =
    //     PackUriHelper.CreatePartUri(
    //         new Uri("Resources\Image1.jpg", UriKind.Relative));
    Uri partUriDocument = PackUriHelper.CreatePartUri(
                              new Uri(documentPath, UriKind.Relative));
    Uri partUriResource = PackUriHelper.CreatePartUri(
                              new Uri(resourcePath, UriKind.Relative));

    // Create the Package
    // (If the package file already exists, FileMode.Create will
    //  automatically delete it first before creating a new one.
    //  The 'using' statement insures that 'package' is
    //  closed and disposed when it goes out of scope.)
    using (Package package =
        Package.Open(packagePath, FileMode.Create))
    {
        // Add the Document part to the Package
        PackagePart packagePartDocument =
            package.CreatePart(partUriDocument,
                           System.Net.Mime.MediaTypeNames.Text.Xml);

        // Copy the data to the Document Part
        using (FileStream fileStream = new FileStream(
               documentPath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartDocument.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri,
                                   TargetMode.Internal,
                                   PackageRelationshipType);

        // Add a Resource Part to the Package
        PackagePart packagePartResource =
            package.CreatePart(partUriResource,
                           System.Net.Mime.MediaTypeNames.Image.Jpeg);

        // Copy the data to the Resource Part
        using (FileStream fileStream = new FileStream(
               resourcePath, FileMode.Open, FileAccess.Read))
        {
            CopyStream(fileStream, packagePartResource.GetStream());
        }// end:using(fileStream) - Close and dispose fileStream.

        // Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(
                                new Uri(@"../resources/image1.jpg",
                                UriKind.Relative),
                                TargetMode.Internal,
                                ResourceRelationshipType);
    }// end:using (Package package) - Close and dispose package.
}// end:CreatePackage()

//  --------------------------- CopyStream ---------------------------
/// <summary>
///   Copies data from a source stream to a target stream.</summary>
/// <param name="source">
///   The source stream to copy from.</param>
/// <param name="target">
///   The destination stream to copy to.</param>
private static void CopyStream(Stream source, Stream target)
{
    const int bufSize = 0x1000;
    byte[] buf = new byte[bufSize];
    int bytesRead = 0;
    while ((bytesRead = source.Read(buf, 0, bufSize)) > 0)
        target.Write(buf, 0, bytesRead);
}// end:CopyStream()

'  -------------------------- CreatePackage --------------------------
''' <summary>
'''   Creates a package zip file containing specified
'''   content and resource files.</summary>
Private Shared Sub CreatePackage()
    ' Convert system path and file names to Part URIs. In this example
    ' Dim partUriDocument as Uri /* /Content/Document.xml */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Content\Document.xml", UriKind.Relative))
    ' Dim partUriResource as Uri /* /Resources/Image1.jpg */ =
    '     PackUriHelper.CreatePartUri(
    '         New Uri("Resources\Image1.jpg", UriKind.Relative))
    Dim partUriDocument As Uri = PackUriHelper.CreatePartUri(New Uri(documentPath, UriKind.Relative))
    Dim partUriResource As Uri = PackUriHelper.CreatePartUri(New Uri(resourcePath, UriKind.Relative))

    ' Create the Package
    ' (If the package file already exists, FileMode.Create will
    '  automatically delete it first before creating a new one.
    '  The 'using' statement insures that 'package' is
    '  closed and disposed when it goes out of scope.)
    Using package As Package = Package.Open(packagePath, FileMode.Create)
        ' Add the Document part to the Package
        Dim packagePartDocument As PackagePart = package.CreatePart(partUriDocument, System.Net.Mime.MediaTypeNames.Text.Xml)

        ' Copy the data to the Document Part
        Using fileStream As New FileStream(documentPath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartDocument.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add a Package Relationship to the Document Part
        package.CreateRelationship(packagePartDocument.Uri, TargetMode.Internal, PackageRelationshipType)

        ' Add a Resource Part to the Package
        Dim packagePartResource As PackagePart = package.CreatePart(partUriResource, System.Net.Mime.MediaTypeNames.Image.Jpeg)

        ' Copy the data to the Resource Part
        Using fileStream As New FileStream(resourcePath, FileMode.Open, FileAccess.Read)
            CopyStream(fileStream, packagePartResource.GetStream())
        End Using ' end:using(fileStream) - Close and dispose fileStream.

        ' Add Relationship from the Document part to the Resource part
        packagePartDocument.CreateRelationship(New Uri("../resources/image1.jpg", UriKind.Relative), TargetMode.Internal, ResourceRelationshipType)

    End Using ' end:using (Package package) - Close and dispose package.

End Sub


'  --------------------------- CopyStream ---------------------------
''' <summary>
'''   Copies data from a source stream to a target stream.</summary>
''' <param name="source">
'''   The source stream to copy from.</param>
''' <param name="target">
'''   The destination stream to copy to.</param>
Private Shared Sub CopyStream(ByVal source As Stream, ByVal target As Stream)
    Const bufSize As Integer = &H1000
    Dim buf(bufSize - 1) As Byte
    Dim bytesRead As Integer = 0
    bytesRead = source.Read(buf, 0, bufSize)
    Do While bytesRead > 0
        target.Write(buf, 0, bytesRead)
        bytesRead = source.Read(buf, 0, bufSize)
    Loop
End Sub

Комментарии

Пакет.Open метод использует ZipPackage контейнеры по умолчанию.

Свойства

Методы

Явные реализации интерфейса

Применяется к

См. также раздел

• PackagePart